A uniform stick 1.4 m long with a total mass of 260 g is pivoted at its center. A 4.0-g bullet is shot through the stick midway between the pivot and one end The bullet approaches at 250 m/s and leaves at 140 m/s. (Figure 1) With what angular speed is the stick spinning after the collision? Express your answer using two significant figures. Figure 250 m/s 1 of 1 140 m/s Pivot W = ΜΕ ΑΣΦ Submit Request Answer Provide Feedback ? rad/s

Two small 0.55-kg masses are attached to opposite ends of a very lightweight rigid rod 0.7 m long. The system is spinning in a horizontal plane around a vertical axis perpendicular to the rod located halfway between the masses. Each mass is moving in a circle of radius 0.35 m at a speed of 0.85 m/s. What is the total angular momentum of this system? kg-m²/s Need Help? Read It

A 0.02 kg mass red object (bead) is moving at a speed of 10.0 m/s when it sticks to the edge of a uniform solid cylinder. The cylinder is free to rotate about its axis through its center and has a mass of 0.5 kg , a radius of 0.25 m and is initially at rest. I = 1/2MR​2^2 a) What is the angular velocity of the system after the collision? b) How much kinetic energy is lost in the collision? c) If the angular position of the Cylinder varies as θ(t)=3.2t-t​^2 ​find the centripetal acceleration of the red object (bead). d) A cord is now wrapped around the cylinder. Use the work energy theorem to find the angular velocity of the cylinder after 5.0m of cord have been removed by a 40N Force. e) If the 40N force on the cord is replaced by a 40-N weight, what is the angular velocity of the cylinder after 5.0m of cord has unwound?

A sanding disk with a rotational inertia of 1.2 x 10-3kgm2 is attached to an electric drill whose motor delivers a torque of 16 Nm.  If the torque is applied for 25 ms and the disk starts from rest, what is the magnitude of the angular velocity of the sanding disk?  Use the rotational version of the Impulse Momentum Theorem.  Take note of the time units.