College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- A sanding disk with a rotational inertia of 1.2 x 10-3kgm2 is attached to an electric drill whose motor delivers a torque of 16 Nm. If the torque is applied for 25 ms and the disk starts from rest, what is the magnitude of the angular velocity of the sanding disk? Use the rotational version of the Impulse Momentum Theorem. Take note of the time units.arrow_forwardA diver (m = 60 kg) jumps from a diving board. At takeoff, his angular momentum about the transverse axis is 30 kg⋅m2/s. His radius of gyration about the transverse axis is 0.5 m at this instant. During the dive, he tucks and reduces his radius of gyrations about the transverse axis to 0.2 m. At takeoff, what is the diver’s moment of inertia about his transverse axis?arrow_forwardA 45 kg figure skater is spinning on the toes of her skates at 1.5 rev/s. Her arms are outstretched as far as they will go. In this orientation, the skater can be modeled as a cylindrical torso (40 kg, 20 cm average diameter, 160 cm tall) plus two rod-like arms (2.5 kg each, 70 cm long) attached to the outside of the torso. The skater then raises her arms straight above her head. In this latter orientation, she can be modeled as a 45 kg, 20-cm-diameter, 200-cm-tall cylinder.What is her new rotation frequency, in revolutions per second?Express your answer in revolutions per second.arrow_forward
- The moment of inertia I of a cheap door of mass M = 4.00 kg (about an axis going through the hinges at the door frame) is I= (1/3) M · R², where R= 0.960 m is the width of the door. The door is initially open and at rest. The door suddenly is struck by a huge and heavy dart of mass m = 0.300 kg traveling perpendicular to the plane of the door at a speed vi = 20.0 m/s. The dart perforates the wooden door getting permanently stuck at the point of impact, which happened to be right next to the free vertical edge of the door (close to the handle). Because the dimensions of the dart are so small (even though they are exaggerated in the picture for clarity) compared to its distance R to the rotational axis (the distance from the hinge to the free vertical edge next to which the dart strikes the door, which is the width of the door R) we can treat the dart as a point mass. I remind you that we learned in class that the moment of inertia of a point mass is I, = m-R², where R is the…arrow_forwardA spherical satellite of approximately uniform density with radius 4.8 m and mass 215 kg is originally moving with velocity (2600, 0, 0) m/s, and is originally rotating with an angular speed 2 rad/s, in the direction shown in the diagram. A small piece of space junk of mass 6.0 kg is initially moving toward the satellite with velocity (-2200, 0, 0) m/s. The space junk hits the edge of the satellite as shown in the figure below, and moves off with a new velocity ( 1300, 480, 0) m/s. Both before and after the collision, the rotation of the space junk is negligible. V3 L Part 1 Ux = Uy = @1 (a) Just after the collision, what are the components of the center-of-mass velocity of the satellite (v, and vy) and its rotational speed w? (For Ux, enter your answer to at least four significant figures.) Part 2 Mi @= i i Save for Later i M, R, 1 V2 m m/s m/s rad/s (b) Calculate the rise in the internal energy of the satellite and space junk combined. J Attempts: 0 of 10 used Submit Answerarrow_forwardA rod of mass M = 3.25 kg and length L can rotate about a hinge at its left end and is initially at rest. A putty ball of mass m = 65 g, moving with speed v = 5.25 m/s, strikes the rod at angle θ = 51° from the normal at a distance D = 2/3 L, where L = 1.3 m, from the point of rotation and sticks to the rod after the collision. 1. What is the angular speed ωf of the system immediately after the collision, in radians per second?arrow_forward
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