A homozygous red pigmented female beetle (bb) is bred with a black pigmented male of unknown genotype. It’s unknown if the male homozygous dominant (BB) or heterozygous (Bb) for the pigment trait. The color of their offspring will help identify the genotype of the male. What do you call this method used to determine the genotype of the male beetle? Explain your answer by using Punnett square to show possible offspring genotypes.

What cross will result in a ratio of 3 dominant phenotype offspring for every 1 recessive offspring?    What cross will result in a 1:2:1 genotype ratio in the offspring?    What cross will result in all homozygous recessive offspring?

A farmer is interested in a new colour pattern in his breed of cattle. This trait is controlled by a single autosomal gene (Gene R) with two alleles. The R-allele results in a spotted colour pattern, while the recessive allele causes a solid colour. The farmer has a cow that has the spotted pattern. Can you suggest how the farmer can determine the genotype (RR or Rr) of his cow in a single cross? Describe this cross and provide details on how you would interpret the results.

For the following problem: Identify the gametes for each parent, build a Punnett Square of the probability of offspring. Show the resulting genotype ratios and the resulting phenotype ratios. The submission file on Canvas will typically have a multiple-choice component or may be a fill-in-the-blank question related to genotype and/or phenotype outcomes. Be prepared to address all of these details in the questions. a )In Pansy flowers, a gene for follower color is “incompletely dominant”. All flowers resulting from the cross of a homozygous red (R) flowering plant with a homozygous white (r) flowering plant were pink. If a pink-flowering plant is bred with another pink-flowering plant, determine the probable genotype and phenotype ratios of the offspring. b) The ratio of genotypes is ________________ .c) The ratio of phenotypes (red:pink:white) is ______________.

Spotted lanternfly females were crosses with males possessing short wings (sw) ebony body (e) and sephia (s) eyes, which are recessive traits. 1000 offspring were counted, and the results are shown in the table. below. No determination of sex was made. Using proper notation determine the linkage-genotype of the female parent. Determine the sequence of the three genes and map the distances between them. Calculate the COC and interference in the cross and describe what it means. Phenotype ++ e S SW + s + + + sw e + + + S SW e se + sw + #offspring 332 331 111 121 46 56 7 6

The answer is "D" but can you explain in a short summary why D is the answer please

In the red spotted butterfly there are two traits under investigation.  The wing margin can be either notched (N) or straight (n) and the wing color can be either pale yellow (b) or bright yellow (B).  A bright yellow male with straight wing margins was crossed with a bright yellow female with notched wing margins.  All of the resulting progeny had notched wings and both color patterns were present.  From these data determine the genotypes of the butterflies used in the original cross.

Give typing answer with explanation and conclusion Directions: For the following problem, calculate the probability of the offspring between the cross using the sum and product rule. The parent generation has genotypes of Aa Bb Cc and AA Bb CC. What is the probability the F1 generation would be AA bb cc?