(a) determine the average shear stress and shear strain in each of rubber blocks (b) determine the shear modulus G of the rubber material used in this component.

An extruded polymer beam is subjected to a bending moment M. The length of the beam is L = 500 mm. The cross-sectional dimensions of the beam are b₁ = 33 mm, d₁ = 109 mm, b₂ = 20 mm, d₂ = 20 mm, and a = 6.5 mm. For this material, the allowable tensile bending stress is 16 MPa, and the allowable compressive bending stress is 11 MPa. Determine the largest moment M that can be applied as shown to the beam. b₂ a M B A Answer: M = L d₂ N•m b₁ d₁

If Poisson's ratio is 0.42, the Modulus of rigidity is 70.4225 GPa, and the bulk modulus is 416.66 GPa, then the elastic modulus of elasticity is (3 Points) 300 GPa 300 MPa 200 MPa None 200 GPa

(b) (i) A tensile test specimen made from 0.4% C steel has a circular cross section of diameter d mm and a gauge length of 25 mm. When a load of 4500 N is applied during the test, the gauge length of the specimen extends to 25.02 mm. If the Young's Modulus of the steel is 199 GPa, calculate the diameter of the tensile test specimen used. 4

Please answer d,e,f

Q2c) Listed in the table below is the tensile stress-strain data for different grades of steels. Utilizing the data given answer the three queries given below. Material Yield Tensile Strain at Fracture Elastic StrengthStrengthFractureStrengthModulus (MPa) (MPa) (MPa) (GPa) A 410 1440 0.63 265 410 В 200 220 0.40 105 250 C 815 950 0.25 500 610 D 800 650 0.14 720 210 E Fractures before yielding 650 550 1) Which will experience the greatest percent reduction in area? Why? 2) Which is the strongest? Why? 3) Which is the stiffest? Why?

The stress-strain diagram for a steel alloy having an original diameter of 0.5 in. and a gage length of 2 in. is given in the figure. If the specimen is loaded until it is stressed to 70 ksi, determine the approximate amount of elastic recovery and the increase in the gage length after it is unloaded. o (ksi) 80 70 60 50 40 30 20 10 e (in./in.) 0 04 0.08 0.12 0.16 0.20 0.24 0.28 0 0005 0.0010.0015 0.002 0.0025 0.0030.0035

A copper rod with a diameter of 19 mm, modulus of 110 GPa, and a Poisson’sratio of 0.35 is subjected to tension within the elastic region. Determine the force that will produce a reduction of 0.003 mm in the diameter.

2. A steel bar, whose cross section is 0.55 inch by 4.05 inches, was tested in tension. An axial load of P = 30,500 lb. produced a deformation of 0.105 inch over a gauge length of 2.05 inches and a decrease of 0.0075 inch in the 0.55-inch thickness of the bar. Determine the lateral strain. * Your answer Determine the axial strain. Your answer Determine the Poisson's ratio v. * Your answer Determine the decrease in the 4.05-in. cross-sectional dimension (in inches). * Your answer

The following data were obtained from the tensile test of Aluminum alloy. The initial diameter of testspecimen was 0.505 inch and gauge length was 2.0 inch. Plot the stress strain diagram and determine(a) Proportional Limit (b) Modulus of Elasticity (c) Yield Stress at 0.2% offset (d) Ultimate Stress and(e) Nominal Rupture Stress. Load (lb) Elongation (in.) Initial Dia d1 (in.) Guage Length L1 (in.) Area (in2) Stress (psi) Strain  0 0 0.505 2 0.200195 0 0 2310 0.0022 0.505 2 0.200195 11538.7713 0.0011 4640 0.0044 0.505 2 0.200195 23177.4454 0.0022 6950 0.0066 0.505 2 0.200195 34716.2168 0.0033 9290 0.0088 0.505 2 0.200195 46404.8423 0.0044 11600 0.011 0.505 2 0.200195 57943.6136 0.0055 13000 0.015 0.505 2 0.200195 64936.8084 0.0075 14000 0.02 0.505 2 0.200195 69931.9475 0.01 14400 0.025 0.505 2 0.200195 71930.0031 0.0125 14500 0.06 0.505 2 0.200195 72429.517 0.03 14600 0.08 0.505 2 0.200195 72929.0309 0.04 14800 0.1 0.505 2 0.200195 73928.0588 0.05 14600…