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Concept explainers
A curious polymorphism in human populations has to
do with the ability to curl up the sides of the tongue to
make a trough (“tongue rolling”). Some people can do
this trick, and others simply cannot. Hence, it is an example of a dimorphism. Its significance is a complete
mystery. In one family, a boy was unable to roll his
tongue but, to his great chagrin, his sister could.
Furthermore, both his parents were rollers, and so were
both grandfathers, one paternal uncle, and one paternal
aunt. One paternal aunt, one paternal uncle, and one
maternal uncle could not roll their tongues.
a. Draw the pedigree for this family, defining your
symbols clearly, and deduce the genotypes of as many
individual members as possible.
b. The pedigree that you drew is typical of the inheritance
of tongue rolling and led geneticists to come up with the
inheritance mechanism that no doubt you came up with.
However, in a study of 33 pairs of identical twins, both
members of 18 pairs could roll, neither member of 8 pairs
could roll, and one of the twins in 7 pairs could roll but
the other could not. Because identical twins are derived
from the splitting of one fertilized egg into two embryos,
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- Parents often want to know what is genetically possible for their children. If two parents are carriers for a recessive lethal trait, what are the odds that their child is also a carrier? Many times there is interest in tracking multiple traits at once (not just 1 or 2). The same probability rules apply here, you just multiple all the odds together at once. Imagine two parents. They are both carriers for red hair, one person is blood type AB, the other is type O. They want to know the odds of a daughter with red hair and type B blood. Please do no not do a giant Punnett square! Use probability or individual squares. a. What are the genotypes of the parents? b. What are the odds of each trait (daughter, red hair, type B)arrow_forwardIt has been hypothesized that people who are heterozygous for the allele that causes the deadly genetic condition cystic fibrosis (which, among other symptoms, reduces fertility) are more resistant to the deadly disease tuberculosis. Question - if the cystic fibrosis allel protects against tuberculosis the same what the sickle cell allele protects against malaria, then which of the following should be true in comparison between regions with or with out TB. -cystic fibrosis deaths should be more common in regions with tb - CYSTIic fibrosis deaths should be less common in regions with tb - CYSTIic fibrosis deaths should be equally common in regions with tb -Regional differences in the cystic fibrosis death rate should be purly random and upredictable.arrow_forwardWhy does the word "race" hold little to no value in biological contexts?arrow_forward
- Human hair color ranges from black to many shades of brown to blonde. What can you correctly conclude from this information? A Human hair color is controlled by a single gene. B Human hair color is controlled by environmental factors rather than genes. C Human hair color is controlled by more than one gene. D Black hair is dominant to blonde hair. Answer is C? Can you help me to explain to me step by step?arrow_forwardPhotography booths that claim to produce pictures of what a male or female child of any given couple will look like are beginning to appear in arcades throughout the country. A couple enters the booth, a camera takes their pictures, and then a computer program analyzes and blends the morphologies of the two people to produce images of a male child and a female child they might create. In genetic terms, why will the couple be wasting their money if they buy these computer images? (Respond in at least 2 paragraphs)arrow_forwardDuchenne’s muscular dystrophy (DMD) is an X-linked disease that causes progressive muscle weakness and is often fatal. “XD” represents the wild type allele, and “Xd,” the mutant allele. Jonah is XDXd Y and his brother Pete is Xd Y. Jonah and Pete BOTH have DMD of equal severity and phenotypes. You might have thought Jonah’s DMD would be less severe given his genotype. To better understand the situation, you investigate Jonah’s Xist chromosome region in his defective muscle cells. Which of the following is consistent with his phenotype? (Select all that apply.) The Xd-containing chromosome is inactive in defective muscle cells. The XD-containing chromosome has a methylated Xist promoter. The XD-containing chromosome has an unmethylated Xist promoter. The Xd-containing chromosome is active in defective muscle cells.arrow_forward
- In human beings, the gene for red‑green colorblindness (r) is sex‑linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f). A nonfreckled, normal‑visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled. What is the probability that the first child born to the couple will either be a freckled, colorblind boy or a non‑freckled, normal visioned girl or a non-freckled, normal visioned boy? What is the probability that the first four children born to the couple will be freckled and normal visioned girls?arrow_forwardAlbinism is a recessive trait in humans . A geneticist studies a series of families in which both parents havenormal pigmentation and at least one child has albinism. The geneticist reasons that both parents in these families must be heterozygotes and that albinism should appear in 14 of their children. To his surprise, the geneticist finds that the frequency of albinism among the children of these families is significantly greater than 14. Can you think of an explanation for the higher-than-expected frequency of albinism among these families?arrow_forwardFinger mid-digital hair (M) is dominant over the recessive trait of no mid-digital hair (m). Freckles (F) is dominant over the recessive trait of no freckles (f). (It is important to note that this example of mid-digital hair and freckles cannot be explained with simple genetics, but for the purpose of this question, assume that it can.)A woman that is heterozygous for freckles and has no mid-digital hair is married to a man with no freckles that is heterozygous for mid-digital hair. The couple is expecting a child. Draw a Punnett square of this cross.arrow_forward
- Sickle cell anemia is a genetic disease most common in those of African ancestry that results from the mutation of a single basepair. This mutation results in a change to the hemoglobin protein. In this experiment, “S” will represent the normal allele and “s” thesickle allele. They are codominant alleles. Therefore, SS is normal, Ss is not fatal but mildly symptomatic, and ss is debilitating,painful, and often fatal. After hundreds or even thousands of generations, both alleles are still common in those of African ancestry. How would you explain this?arrow_forwardThe questions below all refer to the following pedigree. The locus for allele D/d determines how cilia function within the body. Mutations at this allele cause abnormal ciliary function, resulting in a clinical disorder characterized by frequent respiratory infections (including in the ears, sinuses, and lungs), as well as infertility. In the pedigree, black circles/squares represent individuals affected by the disorder. White circles/squares represent unaffected individuals. Remember, if a trait is rare in a population (such as this one), we assume individuals marrying into the family are NOT carriers unless the information provided indicates otherwise. A1 A2 II B1 B2 B3 B4. B5 B6_ II C1. C2 C3. C4. C5 IV D1. D2, D4 . D5 Individuals C2 and C3 are considering having additional children. However, having already had a child with this disorder, they visit a genetic counselor to determine what the probability is that their future child would have the disorder. If C2 and C3 have another…arrow_forward
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