A compound containing C, H, and O exhibits broad absorption at 3450 cm-1 (m) and an intense band at 1725, plus a band at 1100 cm-1 (m). Relative absorption intensity: (s)=strong, (m)=medium, (w)=weak. What functional class(es) does the compound belong to?

The functional groups in an organic compound can frequently be deduced from its infrared absorption spectrum. A compound containing no nitrogen exhibits strong, broad absorption across the 2500-3300 cm-1 region, accompanied by 2200 (w) and 1715 (s) cm-1bands.Relative absorption intensity: (s)=strong, (m)=medium, (w)=weak. What functional class(es) does the compound belong to? List only classes for which evidence is given here. Attach no significance to evidence not cited explicitly.Do not over-interpret exact absorption band positions. None of your inferences should depend on small differences like 10 to 20 cm-1. The functional class(es) of this compound is(are)fill in the blank 1.(Enter letters from the table below, in any order, with no spaces or commas.) a. alkane (List only if no other functional class applies.)   b. alkene h. amine c. terminal alkyne i. aldehyde or ketone d. internal alkyne j. carboxylic acid e. arene k. ester f. alcohol l. nitrile g. ether

The IR and 1H-NMR spectra of a compound with molecular formula C4H7ClO2 are shown below. Your objective as a group is to propose a structure for this compound, explaining how you reach your decision. Using all the information you have been given, in a post with others in your group share your initial ideas about the possible structure of the compound. Then use comments to interact with the other students in the group and propose a final answer to the problem. In the comment phase, you should comment on the postings of at least two other students.

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Use the spectral information given below to derive a structural formula for unknown II. Its molecular formula is C4H100. LO0 IR Spectrum of Unknown II 80 %T 60 40 20 2000 Wavenumbers (cm-1) 4000 3000 1500 1000 400 HNMR Spectrum of Unknown II 9H S S 1H 5 3 2 PPM C13NMR Spectrum of Unknown II 70 60 50 40 PPM 30 20 10

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The functional groups in an organic compound can frequently be deduced from its infrared absorption spectrum. A compound contains no nitrogen and exhibits absorption bands at 3300 (s) and 2150 (m) cm ¹¹. Relative absorption intensity: (s)=strong, (m)=medium, (w)=weak. What functional class(es) does the compound belong to? List only classes for which evidence is given here. Attach no significance to evidence not cited explicitly. Do not over-interpret exact absorption band positions. None of your inferences should depend on small differences like 10 to 20 cm³¹. The functional class(es) of this compound is(are) . (Enter letters from the table below, in any order, with no spaces or commas.) a. alkane (List only if no other functional class applies.) b. alkene c. terminal alkyne d. internal alkyne e. arene f. alcohol g. ether Submit Answer h. amine i. aldehyde or ketone j. carboxylic acid k. ester I. nitrile Retry Entire Group 9 more group attempts remaining

question attached:

The IR and 1H-NMR spectra of a compound with molecular formula C4H7ClO2 are shown below. Your objective is to propose a structure for this compound, explaining how you reach your decision.

Considering IR spectroscopy, which of the following statements is incorrect?    options:   Concentrated alcohols give rise to broad signals while dilute alcohols give rise to narrow signals   Carboxylic acids exist as dimer due to hydrogen bonding and thus produce a narrow signal at 3600 cm-1 and a characteristic signal due to C=O at 1700 cm-1   C=O bonds produce strong signals in an IR spectrum while C=C bonds often produce a weak signals   Symmetrical C=C bonds and C≡C bonds do not produce signals   Primary amines produce two signals resulting from symmetric stretching and asymmetric stretching