College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- answer in Three significant digitsarrow_forwardI have no clue why this problem is being rejected. I have submitted similar problems and have been answered. Can I please get some help with this. Thank you!arrow_forwardThe velocity vx (in m/s) of an object is given by the equation vx = 4t + 3, where t is the time in seconds. Part A The displacement of the object between t = 1 s and t = 2 s is: 9 m 14 m 5 m 7 m Part B The acceleration of the object at t = 2 s is: 11 m/s2 14 m/s2 7 m/s2 4 m/s2arrow_forward
- Shown below is a graph of velocity-versus-time for a moving object. The object starts at position x = 0 m at t = 0 s. What is the final position at t = 4.0 s, in meters?arrow_forwardUsing the following graph and data table please find: horizontal & vertical velocity, and the velocity at 0.155 sec and 0.255 sec (w) x (w) A Time (sec) 0.000 0.033 0.066 0.100 0.133 0.166 0.200 0.233 1.20 1.0 0.8 0.6 0.4 0.2 0 0 0.266 0.300 0.333 0.366 0.400 0.05 0.10 ● x (m) 1.200 1.141 1.079 1.017 0.959 0.899 0.837 0.779 0.717 0.657 0.601 0.546 0.489 0.15 0.20 time (s) 0.25 ... y (m) 1.051 1.040 1.017 0.980 0.933 0.878 0.806 0.730 0.636 0.536 0.416 0.303 0.174 0.30 ● 0.35 ● 0.40arrow_forwardA particle starts from rest and accelerates as shown in the figure below. az (m/s²) 1 15 20 (s) 7 " 5 10 -1 -2 -3 (a) Determine the particle's speed at t = 10.0 s. m/s Determine the particle's speed at t = 20.0 s? m/s (b) Determine the distance traveled in the first 20.0 s. (Enter your answer to one decimal places.)arrow_forward
- A sports car is to travel from A to B in exactly 40 seconds. The distance between A to B is 540 m. The car accelerates at 1.8 m/sec2, then travel at a constant speed for some time before it decelerates at 1.8 m/sec2. The car starts from rest at A and comes to rest at B. Find the maximum speed. Draw the a-t, v-t and s-t graphs to solve the problem.arrow_forwardv = d = df – di . a = v = vf – vi .t t f – t I t t f – tivf = vi + a t v = ½ ( vf + vi )d = ½ ( vf + vi ) t d = vi t + ½ a t2vf2 = vi2 + 2 a d #7/23 on the pagearrow_forwardA car starts from rest. It accelerates at constant acceleration for 5.0 seconds during which the car covers a distance of 125 m. After that the car continues at that speed for 22 seconds, after which the car slows down at a constant deceleration of – 4.5 m/sec2 until coming to a complete stop. Draw a v vs t, graph, label all the relevant data, and use the graphical method to determine total distance traveled.arrow_forward
- You qualitatively analyzed the motion of a van earlier. Now, using the example of the ball thrown into the air, you can do a more detailed analysis of the van's motion. The table shown here includes the time and position data, with one worked example for finding acceleration. Time Position Velocity Ad Acceleration t(s) (m/s) Ar (m/s") 0.0 0.0 6.0 2.0 12 +3.0 12 4.0 36 Sample Calculation Notice that the velocity that will be plotted at t = 1.0 s is the average velocity between t = 0.0 s and t 2.0 s. The velocity that will be plotted at t 3.0 s is the average velocity between t = 2.0 s and 4.0 s. The acceleration that will be plotted at t= 2.0 s is the average acceleration between t = 1.0 s and t = 3.0s. 6.0 48 8.0 96 10.0 142 12.0 190 14.0 226 16.0 250 Adgd-d 12 m-0.0 m 2.0 s-0.0 s V = 18.0 262 Alo2 t2-lo 12 m 2.0 s %3D Analyze and Conclude 1. How well do the average and instantaneous velocities that you calculated agree with = 6.0 m each other? 36 m-12 m V= Afz4 %3D %3D 2 Separate the…arrow_forwardA car is initially at rest on a straight road. The qraph shows the acceleration of the car along that road as a function of time. 4. -2 4. 7. 9 10 11 12 13 14 tis) What is the speed of the car at t=6 s? Batmt Antr Incompatible units. No conversion found between "a/s-1" and the required units. e Tries 0/99 Previous Tries How much distance does the car cover in the first 9 seconds? 44.0 m You are correct. Your receipt no. is 160-3796 Previous Tries What is the speed of the car at t=13 s? Sum A r Submission not graded. Use more significant figures. Tries 0/99 Previous Tries Determine the distance covered by the car between t311 s and t-14 s? Suit A e Tries 0/99arrow_forwardA group of students in a science class monitored the movement of a cat walking along with a straight line and recorded the cat's position in five-second intervals.The results are summarized it in the table below. time and position time(s) position (cm) 0 49.0 5 38.0 10 43.0 15 40.0 20 60.0 A. What is the displacement of the cat between t = 5.00 s and t = 20.0 s? B. What is the average velocity of the cat between t = 5.00 s and t = 20.0 s? C.What is the distance the cat traveled between t = 5.00 s and t = 20.0 s?arrow_forward
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