A particle moves along the x axis beginning at x = −2 m at time zero. The particle moves forward at speed 4 m/s for 3 seconds, then backward at 3 m/s for 2 seconds, then forward again at 1 m/s for 3 seconds. Draw a position vs. time graph for this motion.

The strategy to use when calculating the force exerted by a set of several point charges is to find first the forces exerted by each of the point charges individually. The force exerted by the entire set of charge is the net force resulting from the forces exerted by the individual charges. The forces from the individual charges in this problem are shown in the diagram below. F12 191 0.100 m FR F13 93 0.316 m so the magnitude of this repulsive force is given by the following equation %3D The charge q, exerts a repulsive force F, 2 on q, as shown in the diagram. The distance separating these charges is r,2 where k, is the Coulomb constant in SI units. e 19,|1921 F12 = k r12 c2) х 10-18 (8.99 x 109 N · m²/c2)- ? m)* x 10-6 N

Please Asap

Basam is standing on the edge of a cliff and tosses her physics book upward with a speed of 22.0 m/s. It hits the ground at the base of the cliff 6.0 s later. Create a VELOCITY-TIME graph that represents this scenario. You may assume that the acceleration of the textbook is -9.81 m/s². Use the graph to determine a) the height of the cliff. b) the speed of the book when it impacts the ground. DO NOT use kinematics formulas to solve this problem. This task is assessing your understanding of GRAPHING to represent accelerate motion.

A car with an unknown initial velocity accelerates over the course of 6.00 s to a velocity of 30.0 m/s, after which the car continues at a constant velocity for another 4.00 s. Part A Vo = velocity (m/s) m/s ? ? If the car travels a total distance of 294 m (in the entire 10.00 s interval) what was the initial velocity? 0 1 2 3 velocity vs time 4 5 6 time (seconds) 7 8 9 10 11

I have no clue why this problem is being rejected. I have submitted similar problems and have been answered. Can I please get some help with this. Thank you!

Bob is cruising leisurely on his bike at 2 m/s when Jim passes him, traveling at a constant 10 m/s. Bob immediately begins accelerating at 2.2 m/s² until he reaches his maximum velocity of 13.5 m/s. He continues cruising at that speed until he catches Jim. How long did it take him to catch up to Jim? (Assume the clock started at the instant he began to accelerate.) t = How far did he have to go to catch up to Jim? Ax = %3D

ates) Tılı 80 1. The following graph displays the position of an object versus time. x(t) (m) 4 ● Accessibility: Investigate 2 The acceleration is positive The velocity is negative The speed is +0.5 m/s The position is at a maximum The object is still 900 2 4 Normal tv Using the graph, match each description of motion to the correct time interval. Not all given options are answers. No Spacing H + 6 8 10 Heading 1 MacBook Air t (sec) a) 0 4 e f) only 8 < t < 10 g) t < 2 h) none of the above DII Headine ● X . Fo

Shown below is a graph of velocity-versus-time for a moving object. The object starts at position x = 0 m at t = 0 s. What is the final position at t = 4.0 s, in meters?

Hand written solutions are strictly prohibited.