A bar is attached to the spring at the point C. The left end of the bar is pin supported and can rotates about the pin at Point A. The mass of the bar is m=20kg. The total length of the bar is LAB=3m and LAC=2m. Point A is 0.6 m below the ceiling. A clockwise constant couple moment M= 30Nm is applied on the bar so that the bar rotates from the horizontal position with θ=0° to the vertical position with θ=90°. The spring always maintains at the vertical position. The spring’s stiffness coefficient is k=30N/m and its unstretched length is 0.5 m. The acceleration due to gravity g=9.81 m/s2. During the process that the bar rotates from the horizontal position (state 1) to the vertical position (state 2), determine the following. 5) when use T to represent kinetic energy, V potential energy, U work done and if the bar is at rest at state 1, the principle of work-energy in this case could be expressed as____________ . ∑U(1-2)=T2+V2 T1+V1=T2+V2 T1+∑U(1-2)=V2 V1+∑U(1-2)=T2+V2 A bar is attached to the spring at the point C. The left end of the bar is pin supported and canrotates about the pin at Point A. The mass of the bar is m=20kg. The total length of the bar isLAB=3m and LAC-2m. Point A is 0.6 m below the ceiling. A clockwise constant couplemoment M= 30Nm is applied on the bar so that the bar rotates from the horizontal positionwith 8=0° to the vertical position with 8-90°. The spring always maintains at the verticalposition. The spring's stiffness coefficient is k=30N/m and its unstretched length is 0.5 m. Theacceleration due to gravity g=9.81 m/s². During the process that the bar rotates from thehorizontal position (state 1) to the vertical position (state 2), determine the following.5) when use T to represent kinetic energy, V potential energy, U work done and if the bar isat rest at state 1, the principle of work-energy in this case could be expressedasAn=====BDDMBState 1Ο Συ(1-2)=T2+V2O T1+V1=T2+V2O T1+ZU(1-2)=V2O V1+ZU(1-2)=T2+V2CState 2B

Given data: LAB=3 mLAC=2 mM=30 N.mg=9.81 m/s2 Need to drive the relation between the work, kinetic…

Answered: A bar is attached to the spring at the…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A bar is attached to the spring at the point C. The left end of the bar is pin supported and can rotates about the pin at Point A. The mass of the bar is m=20kg. The total length of the bar is L_AB=3m and L_AC=2m. Point A is 0.6 m below the ceiling. A clockwise constant couple moment M= 30Nm is applied on the bar so that the bar rotates from the horizontal position with θ=0° to the vertical position with θ=90°. The spring always maintains at the vertical position. The spring’s stiffness coefficient is k=30N/m and its unstretched length is 0.5 m. The acceleration due to gravity g=9.81 m/s². During the process that the bar rotates from the horizontal position (state 1) to the vertical position (state 2), determine the following.

5) when use T to represent kinetic energy, V potential energy, U work done and if the bar is at rest at state 1, the principle of work-energy in this case could be expressed as____________ .

∑U_(1-2)=T2+V2

T1+V1=T2+V2

T1+∑U_(1-2)=V2

V1+∑U_(1-2)=T2+V2

A bar is attached to the spring at the point C. The left end of the bar is pin supported and can
rotates about the pin at Point A. The mass of the bar is m=20kg. The total length of the bar is
LAB=3m and LAC-2m. Point A is 0.6 m below the ceiling. A clockwise constant couple
moment M= 30Nm is applied on the bar so that the bar rotates from the horizontal position
with 8=0° to the vertical position with 8-90°. The spring always maintains at the vertical
position. The spring's stiffness coefficient is k=30N/m and its unstretched length is 0.5 m. The
acceleration due to gravity g=9.81 m/s². During the process that the bar rotates from the
horizontal position (state 1) to the vertical position (state 2), determine the following.
5) when use T to represent kinetic energy, V potential energy, U work done and if the bar is
at rest at state 1, the principle of work-energy in this case could be expressed
as
A
n
=====
B
DD
M
B
State 1
Ο Συ(1-2)=T2+V2
O T1+V1=T2+V2
O T1+ZU(1-2)=V2
O V1+ZU(1-2)=T2+V2
C
State 2
B

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