A 4-bit magnitude comparator is explained in the attached file. With similar logic, design a 3 bit magnitude comparator. You must show the equations and draw the logic circuit. [Hints: A and B are two numbers each with 3 bits. How can you implement a circuit to compare these two numbers if, A=B, A>B or A
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A 4-bit magnitude comparator is explained in the attached file. With similar
logic, design a 3 bit magnitude comparator. You must show the equations and draw the logic circuit. [Hints: A and B are two numbers each with 3 bits. How can you implement a circuit to compare these two numbers if, A=B, A>B or A<B]
Step by step
Solved in 3 steps with 2 images
- Q3) A - Convert the Excess-3 to binary number : ( 110001011100.10001010)ex-3 B- convert each Gray code to binary: 1-( 011010001001)G 2-(59)DQ1. Show the implementation of 4 bit binary to gray code (shown in below table) converter using either EPROM or PLA. In Gray code only one bit changes at a time. Binary Gray code Decimal equivalent 0000 0000 1 0001 0001 0010 0011 3 0011 0010 4 0100 0110 5 0101 0111 6. 0110 0101 7 0111 0100 8. 1000 1100 1001 1101 10 1010 1111 11 1011 1110 12 1100 1010 13 1101 1011 14 1110 1001 15 1111 1000(c) Figure Q3(c)(i) shows a register and Figure Q3(c)(ii) shows the input waveforms (CLOCK and Data in) to the circuit. A1 A9 A10 A2 Function generator A3 A11 A12 AS A13 A6 A14 A7 A15 Data in Bop.7) ip.r 82p.7) Logic analyser U1 U2 U3 U4 UO 6. 1. 6 1 6 INVERTER 3 CLK 3 CLK oCLK CLK 5 K K 5 K K 4027 Clock Function generator Figure Q3(c)(i) (i) Determine the type of register as shown in Figure Q3(c)(i).
- H.W :- 1) A four logic-signal A,B,C,D are being used to represent a 4-bit binary number with A as the LSB and D as the MSB. The binary inputs are fed to a logic circuit that produces a logic 1 (HIGH) output only when the binary number is greater than 01102-610. Design this circuit. 2) repeat problem 1 for the output will be 0 (LOW) when the binary input is less than 01112-710- Saleem LateefDraw logic diagram for half adder and full adder circuit using Logisim Softwared) Draw the schematics of 4-bit synchronous and asynchronous MOD-8 counters and comment on their pros and cons. e) Calculate the noise margin for a logic gate with the following logic levels: VIL = 1.1 V, VIH = 3.2 V, VOL = 0.6 V, VOH = 4.0 V.
- Q4(a) Adder is divided into three types which are half adder, full adder, and parallel adder. Illustrate the implementation of full adder using half adder with necessary logic gates. (i) (ii) Figure Q4(a)(ii) shows the input timing diagram for a full adder. Illustrate the timing diagrams for output S and Cout- Cin Cout Figure Q4(a)(ii)-72 in decimal equal to . ..in signed binary O a. 10111000 O b. 10111100 O c. 10111101 O d. 10011100IV) Convert Decimal to Hexadecimal (a) 974510 (b) 2976.5410 V) Convert from Binary to Hexadecimal (a) 10010110101012 (b) 111011101.010101012 VI) Convert from Hexadecimal to Binary (a) 7CAB516 (b) AF2.12B16
- Total Number of active low pins in IC74LS138? Options A-7 B-8 C-9 D-10) Convert from Binary to Decimal a) 1011011012 (b) 1110010.1012 I) Using Double Dabble method, convert from Decimal to Binary (a) 255710 (b) 585.31010 III) Convert from Hexadecimal to Decimal (a) 1CB.ED716 (b) AE18A.E8B916Q4(a) Adder is divided into three types which are half adder, full adder, and parallel adder. Illustrate the implementation of full adder using half adder with necessary logic gates. (i) (ii) Figure Q4(a)(ii) shows the input timing diagram for a full adder. Illustrate the timing diagrams for output S and Cout- B Cin Cout Figure Q4(a)(ii) (iii) Given A = 111001 and B = 100010. Construct a 6-bit parallel adder to solve for A + B.