USE PYTHON TO SOLVE A 1000-lb weight is supported by 3 cables as shown in the figure. Note that cable #3 is attached alongthe y-axis, at a distance of d feet from the origin, O. The static equilibrium equations for this structure areT₁5√33T₁71583T₁ +T₂ 0T₂ +dLT3√15810√158where L = √10² + d², length of cable 3Given d= 5 ft, write a script in PYTHON to solve for the three tensionssimultaneously using solve function from NumPy linalg submodule.Use a formatted statement to write your answer to the screen.= 010T₂ + T3-1000 = 0Lx44'(-)O10'2d1000 lb3'y

In this question we have to write a python code for the given image description.Let's code and hope…

A 1000-lb weight is supported by 3 cables as shown in the figure. Note that cable #3 is attached along the y-axis, at a distance of d feet from the origin, O. The static equilibrium equations for this structure are 2 √33 T₁ 2 √33 5 √33 T₁ 7 √158 3 T₁ + T₂ = 0 √158 10 158 V 102 + d², length of cable 3 Given d= 5 ft, write a script in PYTHON to solve for the three tensions simultaneously using solve function from NumPy linalg submodule. Use a formatted statement to write your answer to the screen. where L = T₂ + d T₂ + T3 = 0 10 ī T3 - 1000 = 0 x 4' 4' O O 10 7 P 1000 lb 3'

A 1000-lb weight is supported by 3 cables as shown in the figure. Note that cable #3 is attached along the y-axis, at a distance of d feet from the origin, O. The static equilibrium equations for this structure are 2 √33 T₁ 2 √33 5 √33 T₁ 7 √158 3 T₁ + T₂ = 0 √158 10 158 V 102 + d², length of cable 3 Given d= 5 ft, write a script in PYTHON to solve for the three tensions simultaneously using solve function from NumPy linalg submodule. Use a formatted statement to write your answer to the screen. where L = T₂ + d T₂ + T3 = 0 10 ī T3 - 1000 = 0 x 4' 4' O O 10 7 P 1000 lb 3'

Operations Research : Applications and Algorithms

4th Edition

ISBN:9780534380588

Author:Wayne L. Winston

Publisher:Wayne L. Winston

Chapter11: Nonlinear Programming

Section11.10: Quadratic Programming

Problem 7P

See similar textbooks

Similar questions

Q5/ A beam with a length L is attached to the wall with a cable as shown. A load W = 400 lb. is attached to the beam. The tension force, T, in the cable is given by: T=! WL√/h²+x² hx For a beam with L = 120 in and h=50 in calculate T for x = 10, 30, 50, 70, 90, and 110 in.
An insulated, electrically-heated (100 kW) tank contains400 kg of water at 65°C when its power is lost. Water iswithdrawn at a steady rate of 0.4 kg/s and cold water (at12°C) enters the tank at the same rate. Assume the tankis well-mixed, and neglect heat gains or losses throughthe tank walls. For the water, c=cp=cv=4200 J/kg C(a) Create a script (m-file) in MATLAB to calculate howlong will it take for the tank’s temperature to fall to 25°C.(b) Display the entire program code used for your scriptcreated in MATLAB. Make sure that running the scriptprovides a numeric result and include your name as acomment.
A fixed beam is subjected to a uniformly-distributed load with an intensity of f = 10 N/mm length of L = 200 mm. Now determine the support reaction forces, internal shear forces and moments, then plot its internal shear force and moment diagram. f[N/m] L 1. Define the paramters, use L and f as the variables y X
- The bucket has a weight of 400 N and is being hoisted using three springs, each having an unstretched length of 6 = 0.45 m and stiffness of k = 800 N/m. Determine the vertical distance d from the rim to point A for equilibrium. 400 N D. 120 120° 0.45 m 120° B 3d EF, = 0; 400 – F = 0 d² + (0.45)² 400 N 3d [800 Jd² + (0.45)² -0.45)] = 0 400 d² + (4.5)² |d² + (0.45)² -0.45) = 0.16667 0.45 m d² + (4.5)² d d² + (0.45)² -0.45 d = 0.16667 Jd² + (0.45)² Va? + (0.45)² (d– 0.16667) = 0.45 0.45 m d [d² + (0.45)*] [d° – 2d(0.16667) + (0.16667)°] = (0.45)² d² d* – 0.33334 d + 0.027779 d – 0.0675 d + 0.0056252 = 0 120° 0.45 m d = 0.502 m Ans
Using C language. In the mechanics of deformable bodies, the following relationships can be used to analyze uniform beams subject to distributed loads: dy dx 0 (x) M(x) de dx EI dM dx dV dx = = V(x) = w(x) Where: x = distance along the beam y = deflection 0 = slope E = modulus of elasticity of the beam I = moment of inertia of the cross-section of the beam M(x) = bending moment at x V = shear force at x w(x) = distributed load at x You measure the following deflections at seven points along the length of a uniform beam: 1.125 1.5 1.875 x [m] 0.375 0.75 -0.2571 -0.9484 -1.9689 -3.2262 -4.6414 y [cm] Employ 4th-order approximation for derivatives to compute the bending moment (in kNm), the shear force (in kN), and the distributed load (in kN/m) at the middle or fourth point. Use the following parameter values in your computation: E = 200 GPa, and I = 200 GPa, and I = 0.0003 m4. NOTES: 1. Ask the user for the modulus of elasticity. 2. Ask the user for the moment of inertia. 2.25 2.625…
Suppose we have an 80-lb lead-acid battery. 10% of the weight of the battery is active material on the plates, i.e., we have a total of 8 lb of active Pb and PbO, on the plates that can be used to make electric power. Use the Gibbs free energy method to estimate the total stored energy in the battery. Assume that the open circuit voltage for a lead-acid cell is 2.1 V. [The answer should be a little less than 1 kilowatt-hour of energy.]
Given two particles with Q = 4.30-µC charges as shown in the figure below and a particle with charge q = 1.39 x 10-18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = co.) x = -0.800 m x = 0.800 m (a) What is the net force (in N) exerted by the two 4.30-µC charges on the charge q? (Enter the magnitude.) N (b) What is the electric field (in N/C) at the origin due to the two 4.30-pC particles? (Enter the magnitude.) V N/C (c) What is the electrical potential (in kV) at the origin due to the two 4.30-uC particles? 96.75 V kV (d) What If? What would be the change in electric potential energy (in J) of the system if the charge g were moved a distance d = 0.400 m closer to either of the 4.30-µC particles?
Analysis 2: The voltage potential, v(t), builds up on the loops, based on the orientation of the magnetic field during an MR scan is given by: v(t) = 0.250t4 + 0.166t3 – 0.500 and the voltage at time t= 0 is 0.
Solve the heat flow equation K (aT/ 21 - 0532: at) = (a2T/ax2), where K is PROBLEM %3D the thermal diffusivity of the homogeneous medium. Apply the algorithm to the case of a copper bar of thermal diffusivity of 1.14 cm2/sec with 1 end maintained at 100°C while the other end is held at 0°C. Let the bar be 8 cm long
Fully developed flow moving a 40 cm diameter pipe has the following velocity profile: Radius r, cm 0.02.55.07.510.0 12.5 15.0 17.5 20.0 Velocity v, m/s 0.914 0.890 0.847 0.795 0.719 0.543 0.427 0.204 0 Find the volumetric flow rate Q integrate from 0 to R using the relationship Q = [_0^R_ 2rtrvdr. Where r is the radial axis of the pipe, R is the radius of the pipe and v is the velocity. Solve the problem using two steps. Fit a polynomial curve to the velocity data using polyfit. Integrate the equation using int.
The flanged steel cantilever beam with riveted bracket is subjected to the couple and two forces shown, and their effect on the design of the attachment at A must be determined. Replace the two forces and couple by an equivalent couple M and resultant R at A. The couple is positive if counterclockwise, negative if clockwise. 1.92 KN 0.67 m 1.71 m- 68° A 6 Answers: M = i kN.m R=( i i+ i y I L 460 N.m 10.17 m 10.17 m 1.08 KN j) kN
A 82-W incandescent lamp is connected to a 178-V source and is left burning continously in an otherwise dark staircase. Determine the following: (a) the current through the lamp. (b) the cost (in cents) of operating the light for five hours if electricity costs 9.5 cents per KWh.