College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Your telescope has a 850-mm-focal-length objective and a 22 mm -focal-length eyepiece. One evening you decide to look at the full moon in (Figure 1), which has an angular size of 0.52 ∘ when viewed with the naked eye. What angle (in degrees) does the image of the moon subtend when you look at it through your telescope? Suppose you decide to take a photograph of the moon using your telescope. You position a CCD detector so that it captures the image produced by the objective lens. What is the diameter of that image?arrow_forwardUse the worked example above to help you solve this problem. A diverging lens of focal length f = -9.0 cm forms images of an object situated at various distances. (a) If the object is placed p, = 27.0 cm from the lens, locate the image, state whether it's real or virtual, and find its magnification. cm M = (b) Repeat the problem when the object is at p, = 9.0 cm. cm M = (c) Repeat the problem again when the object is 4.50 cm from the lens. cm M = HINTS: GETTING STARTED I'M STUCK! EXERCISE Use the values from PRACTICE IT to help you work this exercise. Repeat the calculation, finding the position of the image and the magnification if the object is 18.5 cm from the lens. cmarrow_forwardphyarrow_forward
- An antelope is 20.0 m from a converging lens with a focal length of 30.0 cm. The lens forms an image of theanimal. If the antelope runs away from the lens at a speed 5.00 m/s, how fast is the image moving? Does the imagetoward or away from the lens?arrow_forwardOne positive lens (focal length = f1) and one negative lens (focal length = -f2) are placed at a distance d. – All lenses are thin lenses. Find the overall ABCD matrix of the system Find the value of d when “C” of the overall matrix is zero. ( Hint : Find d in terms of f1 and f2) (This is when the focal length of the overall system is infinity.)arrow_forwardPlease ASAParrow_forward
- A prescription for an eyeglass lens calls for +3.50 diopters. The lensmaker grinds the lens from a “blank” withand convex front surface of radius of curvature n=1.56of 30.0 cm. What should be the radius of curvature of theother surface?arrow_forwardCurrent Attempt in Progress More lenses. Object O stands on the central axis of a thin symmetric lens. For this situation (see the table below, all distances are in centimeters), find (a) the lens type, converging or diverging, (b) the focal distance f, (c) the image distance i. It also refers to whether (d) the image is real or virtual, and (e) on the same side of the lens as O or on the opposite side. (a) (b) Number (c) Number i (d) w god (e) < (a) (b) Type fp Units Units +12 (c) i m 0.30 (d) (e) R/V I/NI Side NI <arrow_forwardLenses with given radii. Object O stands in front of a thin lens, on the central axis. For this situation, each problem in the table (below) gives object distance p, index of refractionnof the lens, radius r of the nearer lens surface, and radius rɔ of the farther lens surface. (All distances are in centimeters.) Find (a) the image distance i and (b) the lateral magnification m of the object, including signs. Also, determine whether the image is (c) real or virtual, (d) inverted from object O or noninverted, and (e) on the same side of the lens as object O or on the opposite side. (a) (b) (c) (d) (e) m R/V I/NI Side r1 r2 +78 1.56 +33 -48 (a) Number i Units i Units (b) Number MacBook Proarrow_forward
- Use the worked example above to help you solve this problem. The near point of a patients eye is 50.0 cm. (a) What focal length must a corrective lens have to enable the eye to see clearly an object 28.5 cm away? Neglect the eye-lens distance. 50 x cm (b) What is the power of this lens? 2 diopters (c) Repeat part (b), taking into account the fact that, for typical eyeglasses, the corrective lens is 2.00 cm in front of the eye. 2.26 X dioptersarrow_forwardProblem 12: A student wears eyeglasses of power P = -3.75 diopter to correct nearsightedness. The glasses are designed to be worn d = 1.3 cm in front of the eye. Part (a) Input an expression for the far point the student can see without correction, do. Part (b) Numerically, what is the distance in meters?arrow_forward
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