Problem 3: An object 5.0 mm high is placed 12 cm from a spherical concave mirror of radius of curvature 21 cm. (a) Show by ray tracing that the image is virtual or real, and determine the image distance and magnification. (b) Show that the image distance can be computed using the focal length R/2. (c) Compute the image size. You must draw the ray diagram to scale to you may also use drawing/drafting software to draw the diagram.

Work with your neighbors to fill in the table below. If a number has (+) written in front of it, then you must determine if the number should be positive or negative. mirror type concave focal radius of length curv. (+)20 cm +20 cm -40 cm object image magnifi- distance distance cation +10 cm +10 cm +30 cm -10 cm 1.0 real or virtual? inverted. or not?

Assuming the orientation of the object is upright, if the magnification of a mirror or lens is negative, it means that A) the image must be smaller than the object. B) the image must be inverted and smaller than the object. C) the image must be inverted. D) the object must be farther from the mirror (or lens) than the image. E) the image must be farther from the mirror (or lens) than the object.

Spherical refracting surfaces. When an object is placed 9.3 cm in front of a spherical refracting surface the image distance is -15 cm. The index of refraction of the refracting material is 2.7 and it is embedded in transparent material with index of refraction 2.0. Find (a) the radius of curvature r of the surface (including the sign) and determine whether the image is (b) real or virtual and (c) on the same side of the surface as object O or on the opposite side. (a) (b) (c) n1 n2 pr i R/V Side 2.0 2.7 +9.3 -15 (a) Number Units (b) (c) >