People who do very detailed work close up, such as jewelers, often can see objects clearly at a much closer distance than the normal 25.0 cm. What is the power of the eyes of a woman who can see an object clearly at a distance of only 9.25 cm? Assume a distance from the eye lens to the retina of 2.00 cm. power: diopters

A person is to be fitted with bifocals. She can see clearly when the object is between 32 cm and 2.1 m from the eye. The upper portions of the bifocals should be designed to enable her to see distant objects clearly. What power should they have? Answer I’m units of diopters The lower portions of the bifocals should en- able her to see objects comfortably at 25 cm. What power should they have? Answer in units of diopters.

What is the power in diopters of a camera lens that has a 58.5 mm focal length?

Problem 3:  Your camera’s zoom lens has an adjustable focal length ranging from 75 to 150 mm.  Part (a)  What is the maximum power of the lens, Pmax, in diopters?  Part (b)  What is the minimum power of the lens, Pmin, in diopters?

4.5-1) The print in many books averages 4.20 mm in height. How high in mm is the image of the print on the retina when the book is held 34.0 cm from the eye? (Assume the lens-to-retina distance is 2.00 cm. Include the sign of the value in your answer.)  _______mm

The accommodation limits for a nearsighted person's eyes are 16.0 cm and 82.0 cm. When he wears his glasses, he can see faraway objects clearly. At what minimum distance is he able to see objects clearly? cm Need Help? Read It Master It

A person’s prescription for bifocals is –0.139 diopter for distant vision and +3.78 diopters for near vision, the near vision being accomplished by inserts into the distant vision lens. What is the net power of the near vision correction?

Problem 13:  Assume the lens-to-retina distance of the human eye is 2.00 cm. Calculate the power P, in diopters, of the eye when viewing an object 4.5 m away.

Suppose a lens is placed in a device that determines its power as 2.64 diopters. (a) Find the focal length of the lens. f = cm I'M STUCK! (b) Find the minimum distance at which a patient will be able to focus on an object if the patient's near point is 49.3 cm. Neglect the eye-lens distance. cm d min

A farsighted eye is corrected by placing a converging lens in front of the eye. The lens will create a virtual image that is located at the near point (the closest an object can be and still be in focus) of the viewer when the object is held at a comfortable distance, usually taken to be 25.0 cm.25.0 cm. If a person has a near point of 49.5 cm,49.5 cm, what power reading glasses should be prescribed to treat this hyperopia? Assume that the distance from the eye to the lens is negligible