8.1 For an NMOS differential pair with a common-mode voltage VCM applied, as shown in Fig. 8.2, let Vpp = Vss = 1.0 V, k, = 0.4 mA/V, (WIL), , = 12.5, V, = 0.5 V, I= 0.2 mA, R, = 10 k, and neglect channel-length modulation. СМ DD SS tn (a) Find Voy and Ves for each transistor. (b) For Vcy=0, find V, Ipp Ip2, V pv and 2- (c) Repeat (b) for V (d) Repeat (b) for Ve (e) What is the highest value of Voy for which Q, and Q, OV GS СМ D1> 'D2> D1» D2° ey=+0.3 V. СМ y=-0.1 V. СМ СМ 1 remain in saturation? (f) If current source I requires a minimum voltage of 0.2 V to operate properly, what is the lowest value allowed for V. and hence for V. CM? СМ

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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8.1 For an NMOS differential pair with a common-mode
voltage Vcy applied, as shown in Fig. 8.2, let Vpp = Vss =
1.0 V, k, = 0.4 mA/V², (WIL),2 = 12.5, V,= 0.5 V, I= 0.2
mA, R, = 10 k2, and neglect channel-length modulation.
СМ
DD
SS
n
tn
(a) Find Vor and Ves for each transistor.
(b) For Vey= 0, find Vs, Ip1, Ip2, V D13 and V2:
(c) Repeat (b) for V
(d) Repeat (b) for VCM=-0.1 V.
(e) What is the highest value of Voy for which Q, and Q,
OV
GS
СМ
S» 'D1>
D2>
CM =+0.3 V.
||
СМ
СМ
СМ
remain in saturation?
(f) If current source I requires a minimum voltage of 0.2 V
to operate properly, what is the lowest value allowed for Ve
and hence for VcM?
СМ
Transcribed Image Text:8.1 For an NMOS differential pair with a common-mode voltage Vcy applied, as shown in Fig. 8.2, let Vpp = Vss = 1.0 V, k, = 0.4 mA/V², (WIL),2 = 12.5, V,= 0.5 V, I= 0.2 mA, R, = 10 k2, and neglect channel-length modulation. СМ DD SS n tn (a) Find Vor and Ves for each transistor. (b) For Vey= 0, find Vs, Ip1, Ip2, V D13 and V2: (c) Repeat (b) for V (d) Repeat (b) for VCM=-0.1 V. (e) What is the highest value of Voy for which Q, and Q, OV GS СМ S» 'D1> D2> CM =+0.3 V. || СМ СМ СМ remain in saturation? (f) If current source I requires a minimum voltage of 0.2 V to operate properly, what is the lowest value allowed for Ve and hence for VcM? СМ
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