8. Consider the following 1/ с сode void setArray(int int i=5; compare (4, i) int compare (int a, if (sub(a, b) return 1 else return 0;
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- Q: CONVERT FOLLOWING C CODE INTO ARM ASSEMBLY CODE #include<stdio.h>int main() {int i, space, rows = 8, star=0; for(i = 0; i < rows-1; i++) {for(space = 1; space < rows-i; space++) {printf(" ");}for (star = 0; star <= 2*i; star++) {if(star==0 || star==2*i)printf("*");elseprintf(" ");}printf("\n");}for(i=0; i<2*rows-1; i++){printf("*");}return 0;}Implementation of the solution in the C++ or Java language • Implementation of the solution in ARMv8 assembly, with comments explaining the purpose of each line Task 1 An automorphic number is a number n whose square ends in n. For instance, 5 is automorphic, because 52 = 25, which ends in 5. Design and implement an ARMv8 program that reads a positive integer from the user and then calculates and prints all the automorphic numbers (decimal base) that are less than or equal to the entered integer. If the entered integer is not positive, an error message is displayed. As an example, if 100 is entered, the program will print all the automorphic numbers up to 100: 1, 5, 6, 25, 76.Example: The Problem Input File Using C programming language write a program that simulates a variant of the Tiny Machine Architecture. In this implementation memory (RAM) is split into Instruction Memory (IM) and Data Memory (DM). Your code must implement the basic instruction set architecture (ISA) of the Tiny Machine Architecture: //IN 5 //OUT 7 //STORE O //IN 5 //OUT 7 //STORE 1 //LOAD O //SUB 1 55 67 30 55 67 1 LOAD 2- ADD 3> STORE 4> SUB 5> IN 6> OUT 7> END 8> JMP 9> SKIPZ 31 10 41 30 //STORE O 67 //OUT 7 11 /LOAD 1 //OUT 7 //END 67 70 Output Specifications Each piece of the architecture must be accurately represented in your code (Instruction Register, Program Counter, Memory Address Registers, Instruction Memory, Data Memory, Memory Data Registers, and Accumulator). Data Memory will be represented by an integer array. Your Program Counter will begin pointing to the first instruction of the program. Your simulator should provide output according to the input file. Along with…
- MIPS Programming Assignment Part I Rewrite C statements int i = 11; int j = 10; int A[] = { 0x11, 0x22, 0x33 }; int B[] = { 0x0, 0x1, 0x2, 0x3, 0x4, 0x5, 0x6, 0x7, 0x8 }; B[ 8 ] = A[ i - j ]; in MIPS assembly. Assume that addresses of variables i, j, A, and B are loaded into the registers $s3, $s4, $s6, and $s7, respectively: .data i: .word 11 j: .word 10 A: .word 0x11, 0x22, 0x33 B: .word 0x0, 0x1, 0x2, 0x3, 0x4, 0x5, 0x6, 0x7, 0x8 .text la $s3, i # load address of i la $s4, j # load address of j la $s6, A # load address of A la $s7, B # load address of B When you finished programming, add a comment at the end of your code which specifies what value is assigned to the location of B[8] after the program executes. Part IIWrite MIPS Assembly program that allows the user to enter a string of text. Determine whether the entered string is a palindrome (a word or a phrase that reads the same backward as forward, like "kayak" and "level") and print the result on the screen.please modify the c language program into a pep 9 assembly language #include <stdio.h> int num, answer; int divide ( int numer, int denom ) { int quotient, remain; remain = numer; quotient = 0; while ( remain >= denom ) { remain -= denom; quotient++; } // end for return quotient; } // end of divide( ) int modulus ( int n, int d ) { int quot, rem; rem = n; quot = 0; while ( rem >= d ) { rem -= d; quot++; } // end for return rem; } // end of modulus( ) int main() { printf("? "); scanf("%d", &num); answer = divide(num, 20); printf("%d / 20 = %d\n", num, answer); answer = modulus(num, 20); printf("%d mod 20 = %d\n", num, answer); answer = divide(num, 35); printf("%d / 35 = %d\n", num, answer); answer = modulus(num, 35); printf("%d mod 35 = %d\n", num, answer); return 0; } // end of mainTranslate the following C program to Pep/9 assembly language. #include <stdio.h> int myAge; void putNext(int age) {int nextYr;nextYr = age + 1;printf("Age: %d\n", age);printf("Age next year: %d\n", nextYr);} int main () {scanf("%d", &myAge);putNext(myAge);putNext(64);return 0;}
- Translate the following C program to Pep/9 assembly language. #include int inpNum, sum, count, min; int main() { sum = 0; count = 0; min = 32767; printf("? "); scanf("%d", &inpNum); while (inpNum != 0 ) { sum += inpNum; count++; if (inpNum < min) { min = inpNum; } printf("? "); scanf("%d", &inpNum); } // end while printf("Sum printf("Count printf("Min } // end of main = = %d\n", sum); = %d\n", count); %d\n", min);Please translate this to assembly from C language. Comment what each line of the code in assembly is doing. Please do not reference disassembly tools or compilers. Simply translate this to ARM assembly. If you are unsure please pass on this question. Thank you void SVN_SEG(unsigned int n){ int i=0; uint32_t temp=0; SEG_CTL=1; for(i=0; i<4; i++){ temp |= (n&0xF)<<(i*8); n>>4; } temp |= 0x80808080; SEG_DATA = temp; }Convert the following into Pep/9 Assembler: #include using namespace std; int square(int n){ int i; int sq; sq = 0; for (i = 0; i < n; i++){ sq = sq + n; } return sq; } int main (){ int num; cout << "Enter a number: "; cin >> num; cout << num << " squared = " << square(num) << endl; return 0; }
- ASSEMBLY Write assembly code for: int var1 = 1; for(int i = 0; i < 10; i++) var1++;Convert the following into Pep/9 Assembler: #include <iostream>using namespace std;int square(int n){ int i; int sq; sq = 0; for (i = 0; i < n; i++){ sq = sq + n; } return sq;}int main (){ int num; cout << "Enter a number: "; cin >> num; cout << num << " squared = " << square(num) << endl; return 0;} Submit: Source file along with screen captures showing the program running in the Pep simulator.How do you write f(a)+f(b) //f(int32_t x) in ARMS Assembly language?