66% of dog owners allow their dogs to sleep on the bed at night. A group of 102 randomly selected dog owners were surveyed. Use the normal approximation to the binomial distribution to find the following. What is the probability that at least 63 of the dog owners who were surveyed allowed their dogs to sleep on the bed at night? In the dropdown menus below, s and ≥ will be displayed as <= and >= (a) What probability are we being asked to find? ? (b) After performing a continuity correction, what probability will we need to find? ? (c) What are the mean and the standard deviation of the original binomial variable (which we will use for our normal approximation)? μ = ₁0 = (Round all decimals to at least 3 places.) (d) Finally, what is the probability using the normal approximation? at least 3 places.) (Round all decimals to
66% of dog owners allow their dogs to sleep on the bed at night. A group of 102 randomly selected dog owners were surveyed. Use the normal approximation to the binomial distribution to find the following. What is the probability that at least 63 of the dog owners who were surveyed allowed their dogs to sleep on the bed at night? In the dropdown menus below, s and ≥ will be displayed as <= and >= (a) What probability are we being asked to find? ? (b) After performing a continuity correction, what probability will we need to find? ? (c) What are the mean and the standard deviation of the original binomial variable (which we will use for our normal approximation)? μ = ₁0 = (Round all decimals to at least 3 places.) (d) Finally, what is the probability using the normal approximation? at least 3 places.) (Round all decimals to
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 10CYU
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Transcribed Image Text:66% of dog owners allow their dogs to sleep on the bed at night. A group of 102 randomly selected dog
owners were surveyed.
Use the normal approximation to the binomial distribution to find the following.
What is the probability that at least 63 of the dog owners who were surveyed allowed their dogs to sleep
on the bed at night?
In the dropdown menus below, s and 2 will be displayed as <= and >=
(a) What probability are we being asked to find? ?
(b) After performing a continuity correction, what probability will we need to find? ?
(c) What are the mean and the standard deviation of the original binomial variable (which we will use for
our normal approximation)?
H=
₁0=
(Round all decimals to at least 3 places.)
(d) Finally, what is the probability using the normal approximation?
at least 3 places.)
(Round all decimals to
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