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6 > 12 15 1 18 21 An online store owner has conducted a survey. Store survey results: In a random sample of 150 orders, 72 used the PC. To find out if the percentage of PC users in her store is different from the 43% reported by BrizFeel (see the clipping below), the store owner will test store survey results for statistical significance at 0.05 level of significance. Answer the following question: What should be the conclusion of the test at 0.05 level of significance? https://brizfeel.com/consumer-online-retail-shopping-behavior/ BrizFeel Improve Your Home & Life We've surveyed over 30,000 consumers worldwide aged 18 to 65. A Summary of our Most Interesting Survey Findings: 43% of online shoppers use PCs A. B. C. D. Fail to reject Ho. The percentage of PC orders in the store is consistent with the percentage, published by BrizFeel Reject Ho. the percentage of PC orders in the store is consistent with the percentage, published by BrizFeel Reject Ho. the percentage of PC orders in the store is NOT consistent with the percentage, published by BrizFeel Fail to reject Ho. the percentage of PC orders in the store is NOT consistent with the percentage, published.
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- A chemist measures the haptoglobin concentrations (in grams per liter) in the blood of eight healthy adults. Following are the values: 1.82 3.32 1.07 1.27 0.49 3.79 0.15 1.98 At the 2% significance level, test the claim that the mean haptoglobin concentration in adults is less than two grams per liter. What type of error could you have made in your decision?arrow_forwardPast studies have indicated that the percentage of smokers was estimated to be about 34%. Given the new smoking cessation programs that have been implemented, you now believe that the percentage of smokers has reduced. You randomly surveyed 1783 people and found that 553 smoke. Use a 0.05 significance level to test the claim that the percentage of smokers has reduced.arrow_forwardResearchers examined the influence of a television program on children's aggressiveness. The number of aggressive responses was measured during an observation period after viewing the television program. Imagine that the known national average for number of aggressive responses typically performed by children who do not watch television is 6.847. Use the data below to conduct an analysis to determine if the number of aggressive responses on average is different from the national average. The data for this study can be found below, answer questions based on data. What is the null and alternative hypotheses in words and symbols? Is the assumption(s) met? Please explain your answer and proceed with the analysis even if the assumption(s) is not met. What do you conclude from your analysis? Based on your response in “c” above, identify and explain the type of error you could be making. responses 9 4 11 12 14 7 12 10 11 8 14 12 8 12 7 10 10 9 5…arrow_forward
- Which of the following research scenarios uses a two samples independent-measures t test? a. Examine the difference in self-esteem between student athletes and non-athletes. b. Evaluate the effectiveness of a pain reliever by measuring how much pain is reduced after taking the medication in a single group of people who rated pain, then took the drug and rated pain a second time. c. Test the effectiveness of a cholesterol medication by comparing cholesterol levels before and after the medication is administered to a single group. d. Calculating the z score for the highest X in the data set.arrow_forwardSeveral studies showed that after eating a low-fat cereal for two meals a day, subjects had lost some weight.A cereal companyfinanced this research. Identify what is wrong. Choose the correct answer below. A. Since the research is composed of voluntary response samples, there may be key data points missing. B. The data used in the studies is not reliable because it was not measured by the administrator. C. It is questionable that the sponsor is a cereal company because this sponsor can be greatly affected by the conclusion. D. It is not possible to take accurate measurements.arrow_forwardA statistician changes her level of significance from .001 to .05. What impact will this change have on her risk of making a Type I and Type II error? Is the change in the level of significance a good decision? Why or why not?arrow_forward
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