6. A 0.3 m diameter circular duct carries standard air at a velocity of 360 m/min. It is replaced by a rectangular duct having the same pressure loss per unit length due to friction. Determine the dimensions of the rectangular duct if the aspect ratio is to be 1.5 for (a) the same volume flow through the two ducts, and (b) the same velocity in the two ducts. (Ans. 0.336 m. 0.224 m: 0.375 m, 0.25 m

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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5. A duct of 0.45 m diameter and 90 m long leads from a fan discharge chamber where the pressure is
15 mm of water to a plenum chamber where the pressure is 10 mm of water.
In order to increase the flow, two alternatives are considered. One is to lay a duct of 0.3 m diameter
and 90 m long in parallel with the duct of 0.45 m diameter. The other is to increase the diameter of
0.45 m diameter duct for the last 60 m length. Calculate the increased diameter so that this method
gives the same flow as the 0.45 m and 0.3 m ducts in parallel. Assume that the pressures in the fan
chamber and plenum chamber are unaffected by changes in the flow and consider duct friction losses
only. The friction factor may be taken as 0.0o55.
6. A 0.3 m diameter circular duct carries standard air at a velocity of 360 m/min. It is replaced by a
rectangular duct having the same pressure loss per unit length due to friction. Determine the
dimensions of the rectangular duct if the aspect ratio is to be 1.5 for (a) the same volume flow
through the two ducts, and (b) the same velocity in the two ducts.
[Ans. 0.567 m1
[Ans, 0.336 m, 0.224 m: 0.375 m, 0.25 m 1
7. A fan delivers air at 8 m/s to the main line of air conditioning duct. After a straight run of
10 m, a branch of 4 m length delivers air to a room with 2 m'/s. Another branch after a 5 m further
run is taken from the main branch. This branch is 5 m in length and delivers 3 m'/s. The main branch
runs straight for another 5 m and then turns by 90° and runs for another 5 m length and delivers 3 m/
s of air. The losses are given as
For elbow : 0.25 p, where p,
mm of water.
4.04
For branch : 0.2 p, + Elbow loss
For straight through section : 0.25 x Difference of velocity pressure
Fitting losses where change in area occurs.
Find the size of all the ducts and determine the static pressure requirement. Use the following formula
for friction rate :
0.002 268 (0)RS2
(D)4973
where Q is in m'/s and D is in m.
Pr
Find the friction rate in main line and then assume same friction rate for whole of duct work.
(Ans. 1.128 m, 1.01 m : 0.783 m ; 0,905 mm of water; 0.0586 mm of water / m length ]
+ Main duct
8. A main air duct of constant rectangular
cross-section 2 m by 0.6 m has several
branch pieces leading off it. One of these 0.6 m
branches is shown in Fig. 20.28. The
branch leaves the main at right angles
and has a 90° bend in it of radius 0.6 m,
as well as a damper for flow regulation
and an exit grill. The branch is 0.6 m by
0.3 m and 3 m long. The flow through
the main duct before this off take is 750
m'/min and the flow required in the
branch is 90 m'/min. Čalculate the
-Branch
F-2m-
0.6 m
Damper -
Grll
Air outlet
Fig. 20.28
Transcribed Image Text:5. A duct of 0.45 m diameter and 90 m long leads from a fan discharge chamber where the pressure is 15 mm of water to a plenum chamber where the pressure is 10 mm of water. In order to increase the flow, two alternatives are considered. One is to lay a duct of 0.3 m diameter and 90 m long in parallel with the duct of 0.45 m diameter. The other is to increase the diameter of 0.45 m diameter duct for the last 60 m length. Calculate the increased diameter so that this method gives the same flow as the 0.45 m and 0.3 m ducts in parallel. Assume that the pressures in the fan chamber and plenum chamber are unaffected by changes in the flow and consider duct friction losses only. The friction factor may be taken as 0.0o55. 6. A 0.3 m diameter circular duct carries standard air at a velocity of 360 m/min. It is replaced by a rectangular duct having the same pressure loss per unit length due to friction. Determine the dimensions of the rectangular duct if the aspect ratio is to be 1.5 for (a) the same volume flow through the two ducts, and (b) the same velocity in the two ducts. [Ans. 0.567 m1 [Ans, 0.336 m, 0.224 m: 0.375 m, 0.25 m 1 7. A fan delivers air at 8 m/s to the main line of air conditioning duct. After a straight run of 10 m, a branch of 4 m length delivers air to a room with 2 m'/s. Another branch after a 5 m further run is taken from the main branch. This branch is 5 m in length and delivers 3 m'/s. The main branch runs straight for another 5 m and then turns by 90° and runs for another 5 m length and delivers 3 m/ s of air. The losses are given as For elbow : 0.25 p, where p, mm of water. 4.04 For branch : 0.2 p, + Elbow loss For straight through section : 0.25 x Difference of velocity pressure Fitting losses where change in area occurs. Find the size of all the ducts and determine the static pressure requirement. Use the following formula for friction rate : 0.002 268 (0)RS2 (D)4973 where Q is in m'/s and D is in m. Pr Find the friction rate in main line and then assume same friction rate for whole of duct work. (Ans. 1.128 m, 1.01 m : 0.783 m ; 0,905 mm of water; 0.0586 mm of water / m length ] + Main duct 8. A main air duct of constant rectangular cross-section 2 m by 0.6 m has several branch pieces leading off it. One of these 0.6 m branches is shown in Fig. 20.28. The branch leaves the main at right angles and has a 90° bend in it of radius 0.6 m, as well as a damper for flow regulation and an exit grill. The branch is 0.6 m by 0.3 m and 3 m long. The flow through the main duct before this off take is 750 m'/min and the flow required in the branch is 90 m'/min. Čalculate the -Branch F-2m- 0.6 m Damper - Grll Air outlet Fig. 20.28
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