53 You have three sodium carbonate solutions on a lab table in front of you. All of the solutions came from a 500.0-ml. volumetric flask containing 3.00 Af sodium carbonate. Solution 1 contains 137.5 mL of the 3.00 M solution. Solution 2 contains 58.2 mL of the 3.00 M solution, Solution 3 contains 26.8 mL of the 3.00 M solution, How many moles of ions does Solution 1 contain? 1.24 mol 0.413 mol mol 0.825 mol 0.619 mol

Part A transcript When glucose (C6H12O6 (s)) is consumed, it reacts with O₂ gas in the body to produce gaseous carbon dioxide and liquid water. Enter the balanced chemical equation for the reaction. Express your answer as a chemical equation including phases. 0 ΑΣΦ ? A chemical reaction does not occur for this question. Submit Previous Answers Request Answer

diluting a 0.40M CuSO4 stock solution with water, calculate the concentration of each of the solutions ( trials ). Trial  Volume(mL) 0.40M CuSO4 volume(mL) Dl H20 new concentration CuSO4 1 2.0 8.0   2 4.0 6.0   3 6.0 4.0   4 8.0 2.0   5 10.0 0.0

ge.com/course.html?courseld=17842654&OpenVellumHMAC=d71eb8b5068468150149000 For each of the following acid-base reactions indicate whether it will favor reactants or products. Compound pK, CH3COOH 4.8 HCOOH 3.8 15.7 PO H₂O NH3 36 H₂O+ -1.7 CH3 O H₂ -2.5 PresentationO CH_NH,+HO- =CH,NH+H,O O products. reactants Submit ▾ Part B Request Answer NH3 + H₂O + NH4+ HO™ = reactants O products Submit Request Answer P Pearson Copyright © 2023 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy P

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(h) (i) (i) NH₂ (1) (CH3)2NH CHOH acetic acid (1) NaH (2) AIC13 (1) NaH OF (2) Br H Br NMe₂ (1) POC13 (2) Na₂CO3, H₂O

help please answer in text form with proper workings and explanation for each and every part and steps with concept and introduction no AI no copy paste remember answer must be in proper format with all working

A student needs 25.0 mL of 7.18x10 4 M FD&C Blue Dye No. 2 solution. If the student has 2.00 mM FD&C Blue Dye No. 2 stock solution to work with, how much of the 2.00 mM solution should be added to the 25.0 mL volumetric flask? Hint, 2.00 mM is 0.00200 M. O 0.1114 mL O 7.474 mL O 1.114 mL 8.974 mL 2.786 mL

Saved Normal BIIIU fxl Ix Actual mass used in solution prep (g) Volume solution prepared Measured conductivity (uS/cm) Substance 0.1 g Naci 0.1003 100 mL 1149 0.1 g Nal 0.10 100 ml 419 Calculate the mass of Nal that would be necessary to yield the same conductivity as the NaCl solution. Clearly show these calculations in your lab notebook. Saved T BII U X X + fr Normal

The first goal is to make the oxalic acid standard solution.  You measure 1.5232 g of oxalic acid on an analytical balance, add it to a 250-mL volumetric flask and add deionized H2O to a final volume of 250.0 mL.   Molar mass of H2C2O4•2H2O = 126.07 g/mol   Mass of H2C2O4•2H2O = 1.5232g  Volume of H2C2O4•2H2O  solution = 250.0mL    What is the Molarity H2C2O4 standard solution ?