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Step 3 of 8 Sum the equations for d[H] and d[Br] and solve for [Br]. (Use the following as necessary: [Br2], [H], [H2], [HBr], k1, k2, k3, k4, and k5.) dt dt [Br] = K5 2k1 [Br.] 2k [Br2] ks Step 4 of 8 Using the equation for I from Step 2, solve for [H]. (Use the following as necessary: [Br], [Br2], [H2], [HBr], k1, k2, k3, k4, and k5.) dt ky[ Br][H,] kg[Br] + k4 [HBr] [H] = k2[Br][H2] k3[Br2] + k4[HBr] Step 5 of 8 Substitute the equation for [Br] from Step 3 into the equation for [H] from Step 4 and simplify. (Use the following as necessary: [Br2], [H2], k1, k2, k3, k4, and k5.) k, k5 [Br.] [H] k3[Br2] + k4[HBr] Submit

2. An 84 kg University of Toledo groundskeeper who is spraying a 100 mg/L solution of the insecticide dieldrin (MW = 381; logP = 4.56) on some trees exposes 100 cm“ of his skin to the solution over a 4 hr period. Dieldrin has a half-life of about 6 months, a volume of distribution of about 40 L/kg, and a dermal permeability of about 3 x 10° cm/sec. (a) Estimate the absorption rate during the exposure period assuming the blood concentration is much lower than the skin concentration (i.e., take the blood level to be zero in the skin absorption equation). (b) Estimate how it takes after exposure begins for the groundskeeper's plasma dieldrin levels to reach 1 ng/L. (c) Estimate the maximum plasma dieldrin concentration in ng/L that will occur in this groundskeeper due to this exposure. (d) Estimate how long it will take after exposure ends for the groundskeeper's plasma dieldrin levels to drop back down to 1 ng/L. %3D

only answer question four with the correct answer please.