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If 35.45 mL of 0.8121 M sodium carbonate solution reacts with excess lead (III) nitrate solution to form aqueous sodium nitrate and solid lead (III) carbonate, how many grams of lead (III) carbonate is formed?

If 35.45 mL of 0.8121 M sodium carbonate solution reacts with excess lead (III) nitrate solution to form aqueous sodium nitrate and solid lead (III) carbonate, how many grams of lead (III) carbonate is formed?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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--- ### Part 3: SHOW WORK **Raymond Shipp: Attempt 1** --- #### Answer: | | | |-----|-----| --- ### Question 4 (0.5 points) **SHOW YOUR WORK.** If 35.45 mL of 0.8121 M sodium carbonate solution reacts with excess lead (III) nitrate solution to form aqueous sodium nitrate and solid lead (III) carbonate, how many grams of lead (III) carbonate is formed? On your paper with your name and date: 1. Go from ionic compound name to formula (review Chapter 5 as much as needed). 2. Balance the equation (review Chapter 7 if needed). 3. Do the calculation showing **ALL** units, just like I did in solution stoichiometry lecture. --- ### Explanation This is a typical chemistry question involving a reaction between two compounds. The task is to determine the amount of product formed when given specific volumes and molarities of reactants. The steps involve: 1. **Identifying Compounds**: Converting the names of the chemicals into their chemical formulas. 2. **Balancing the Equation**: Ensuring that the reaction adheres to the law of conservation of mass by having equivalent numbers of each atom on both sides of the reaction. 3. **Calculation with Units**: Utilizing stoichiometry to solve for the desired mass of the product, while ensuring all the units (moles, liters, grams, etc.) are correctly applied and canceled out as necessary. This process helps illustrate key principles of stoichiometry, the relationships between the quantities of reactants and products in chemical reactions. ---
Transcribed Image Text:--- ### Part 3: SHOW WORK **Raymond Shipp: Attempt 1** --- #### Answer: | | | |-----|-----| --- ### Question 4 (0.5 points) **SHOW YOUR WORK.** If 35.45 mL of 0.8121 M sodium carbonate solution reacts with excess lead (III) nitrate solution to form aqueous sodium nitrate and solid lead (III) carbonate, how many grams of lead (III) carbonate is formed? On your paper with your name and date: 1. Go from ionic compound name to formula (review Chapter 5 as much as needed). 2. Balance the equation (review Chapter 7 if needed). 3. Do the calculation showing **ALL** units, just like I did in solution stoichiometry lecture. --- ### Explanation This is a typical chemistry question involving a reaction between two compounds. The task is to determine the amount of product formed when given specific volumes and molarities of reactants. The steps involve: 1. **Identifying Compounds**: Converting the names of the chemicals into their chemical formulas. 2. **Balancing the Equation**: Ensuring that the reaction adheres to the law of conservation of mass by having equivalent numbers of each atom on both sides of the reaction. 3. **Calculation with Units**: Utilizing stoichiometry to solve for the desired mass of the product, while ensuring all the units (moles, liters, grams, etc.) are correctly applied and canceled out as necessary. This process helps illustrate key principles of stoichiometry, the relationships between the quantities of reactants and products in chemical reactions. ---
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