504.2 Tensile Strength The design tensile strength, $¿Pn and the allowable tensile strength, Pn/l4, of tension members, shall be the lower value obtained according to the limit states of tensile yielding in the gross section and tensile rupture in the net section. 1. For tensile yielding in the gross section: Pn = FyAg (504.2-1) Pi = 0.90 (LRFD) N, = 1. 67 (ASD) 2. For tensile rupture in the net section: P, = FuAe (504.2-2) P: = 0.75 (LRFD) 1, = 2.00 (ASD) An angle bar 100x100x11 mm tension member is connected with 20-mm-diameter bolts as shown in the figure. Both legs of the angles are connected. Use Fy = 248 MPa and Fu = 400 MPa. 63.5 mm - 6 @ 50 m 63.5 mm 1. Determine the nominal strength for tensile yielding in the gross section. A. 515.59 kN B. 429.67 kN C. 545.60 kN D.390.10 kN 2. Determine the effective net area of member. B. 1,632 mm D.1,815 mm? A. 1,573 mm? C. 1,605 mm? 3. Determine the nominal strength for tensile rupture in the net area. A. 642 kN B. 730 kN C. 554 kN D.650 kN

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Author:Segui, William T.
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504.2 Tensile Strength
The design tensile strength, $¿Pn. and the allowable
tensile strength, Pn/N4, of tension members, shall be the
lower value obtained according to the limit states of
tensile yielding in the gross section and tensile rupture in
the net section.
1. For tensile yielding in the gross section:
Pn = FyAg
(504.2-1)
Pi = 0.90 (LRFD)
N, = 1.67 (ASD)
2. For tensile rupture in the net section:
Pn = F„Ae
(504.2-2)
$: = 0.75 (LRFD)
N = 2.00 (ASD)
An angle bar 100x100x11 mm tension member is connected with 20-mm-diameter
bolts as shown in the figure. Both legs of the angles are connected. Use Fy = 248
MPa and Fu = 400 MPa.
63.5 mm
6 @ 50 mm
63.5 mm
1.
Determine the nominal strength for tensile yielding in the gross section.
A. 515.59 kN
B. 429.67 kN
C. 545.60 kN
D.390.10 kN
2.
Determine the effective net area of member.
B. 1,632 mm
D.1,815 mm?
A. 1,573 mm?
C. 1,605 mm²
3.
Determine the nominal strength for tensile rupture in the net area.
A. 642 kN
B. 730 kN
C. 554 kN
D.650 kN
Transcribed Image Text:504.2 Tensile Strength The design tensile strength, $¿Pn. and the allowable tensile strength, Pn/N4, of tension members, shall be the lower value obtained according to the limit states of tensile yielding in the gross section and tensile rupture in the net section. 1. For tensile yielding in the gross section: Pn = FyAg (504.2-1) Pi = 0.90 (LRFD) N, = 1.67 (ASD) 2. For tensile rupture in the net section: Pn = F„Ae (504.2-2) $: = 0.75 (LRFD) N = 2.00 (ASD) An angle bar 100x100x11 mm tension member is connected with 20-mm-diameter bolts as shown in the figure. Both legs of the angles are connected. Use Fy = 248 MPa and Fu = 400 MPa. 63.5 mm 6 @ 50 mm 63.5 mm 1. Determine the nominal strength for tensile yielding in the gross section. A. 515.59 kN B. 429.67 kN C. 545.60 kN D.390.10 kN 2. Determine the effective net area of member. B. 1,632 mm D.1,815 mm? A. 1,573 mm? C. 1,605 mm² 3. Determine the nominal strength for tensile rupture in the net area. A. 642 kN B. 730 kN C. 554 kN D.650 kN
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Segui, William T.
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Cengage Learning