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5.06-4. Bellman Ford Algorithm (3, part 4). Consider again the same network shown above and again focus on node L. All links have a cost of 1.

5.06-4. Bellman Ford Algorithm (3, part 4). Consider again the same network shown above and again focus on node L. All links have a cost of 1.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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ere 5.06-4. Bellman Ford Algorithm (3, part 4). Consider again the same network shown above and again focus on node L. All links have a cost of 1. Suppose that at time t, the distance vector calculations have completed in all nodes. The link between nodes S and then goes down at time t. Assuming that all nodes exchange distance vectors (DV)s at times t+1, t+2, (i.e., a clock tick is one time unit)... immediately recompute their DVs and if they transmit a new DV do so at the next integer time value. After how many time ticks, will L's distance vector (i.e., its DV that it exchanges with its neighbor) reflect this change in topology? After 1 time tick. After 8 time ticks roughly the diameter of the network. Four time ticks. OL's distance vector will not change so it will not send out a change in DV message - i.e., the algorithm will not iterate. O After 2 time ticks.
Transcribed Image Text:ere 5.06-4. Bellman Ford Algorithm (3, part 4). Consider again the same network shown above and again focus on node L. All links have a cost of 1. Suppose that at time t, the distance vector calculations have completed in all nodes. The link between nodes S and then goes down at time t. Assuming that all nodes exchange distance vectors (DV)s at times t+1, t+2, (i.e., a clock tick is one time unit)... immediately recompute their DVs and if they transmit a new DV do so at the next integer time value. After how many time ticks, will L's distance vector (i.e., its DV that it exchanges with its neighbor) reflect this change in topology? After 1 time tick. After 8 time ticks roughly the diameter of the network. Four time ticks. OL's distance vector will not change so it will not send out a change in DV message - i.e., the algorithm will not iterate. O After 2 time ticks.
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