CONTENTS OF REACTION CUVETTES: (Calculations in PreLab)[ONPG]Diluted ONPG0mMNone0.25mL0.5mL0.75mL1.0mL bloo1.25mL1.5mLBufferLactase0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL0.25mL*** HINT: To calculate [ONPG], cuvette #5 contains 1.0mL ONPG in a total of 2.0mL. (This is the same as a 1:2dilution.) Therefore we divide the concentration of ONPG by 2 to get 5mM.5mMWater1.5mL1.25mL1.0mL0.75mL0.5mL0.25mLNone***4. To perform Lactase Assay with first cuvette ("OmM"):Clean cuvette with Kimwipe.Place cuvette into Spectro Vis with stripes in front in back.GET GROUP READY FOR TIMED ASSAY. AT THE SAME TIME:* Press Record (Green Triangle button).* Add 0.25mL of Lactase to cuvette. Use pipette to quickly mix liquid.WAIT 60 SECONDS! After the assay is complete:* In Experiment menu, select "Store Latest Run" THIS STEP IS NECESSARY!* Record data on the data table below.5. Repeat Step 7 for all of your cuvettes. Record the data below.2viiboloV\:8A11201 201sall rade5. What is the final ONPG concentration (in mM) of each of the Reaction tubes?***Hint: Use the table on in your lab manual to figure this out. ***k moHatesgoutmM of ONPG in Reaction tube= 0mL of ONPG in a total volume of 2mL = 0 (10mM) = 0mM= 0.25 mL of ONPG in a total volume of 2mL = (0.25*10mM)/2 = 1.25mMmL of ONPG in a total volume of 2mL = (______ *10mM)/2 =mM== 1.0mL of ONPG in a total volume of 2mL = ½ (10mm) = 5mMMacBook Pro

The dilution formula is used to calculate the concentration of a solution after it has been diluted.…

Answered: 5. What is the final ONPG concentration…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Analysis of a protein is taking place. The enzymic acivity of this protein is stable up to temperatures of 40 degrees celsius. ph values are between 2.5 and 11.5. Now, Ion exchange chromatography is conducted via a software using DEAE-cellulose and method of elution is done by salt gradient. pH is set to 7. In terms of Molar, start of gradient is 0 and end of gradient is 1. The following graph is generated. Using the graph and analytical methods, determine pI of protein.
The reults for the macroscopic part: 0.30M glycerin – solution was translucent (could see text behind the test tube) 0.15M NaCl – solution was opaque (could not see text behind the test tube) 0.30M NaCl – solution was opaque (could not see text behind the test tube) 0.15M glucose – solution was translucent (could see text behind the test tube) 0.30M glucose – solution was opaque (could not see text behind the test tube) 0.30M Urea – solution was translucent (could see text behind the test tube) Results for microscopic part: 0.30M glycerin – no cells present 0.15M NaCl – normal sized cells 0.30M NaCl – crenated (shrunken and star-shaped) cells 0.15M glucose – no cells present 0.30M glucose – normal sized cells 0.30M Urea – no cells present Determine the osmolarity (hypoosmotic, isosmotic, or hyperosmotic) and tonicity (hypotonic, isotonic, hypertonic) of the following solutions.In which solutions did the osmolarity NOT match the tonicity? For those solutions, why did the osmolarity…
Table 4- Determination of the optimum pH of catechol oxidase enzyme Potato extract (mL) Tube # 2d 3d 4d 5d 6d 7d dH₂O (mL) 0 0 0 0 0 0 Catechol (mL) 6 6 6 6 6 6 pH buffer added 4mL pH 2 4mL pH 4 4mL pH 6 4mL pH 7 4mL pH 8 4mL pH 10 1 1 1 1 1 1 Absorbance (0 mins) A: 0.010 Start Time: 3:24 A: 0.008 Start Time: 3:34 A: 0.023 Start Time: 3:36 A: -0.006 Start Time: 3:36 0.018 A: Start Time: 3:36 A: 0.011 Start Time: 3:36 Absorbance (after 10 mins in 40°C water bath) -0.030 A: Take reading at: 3:44 A: 0.154 Take reading at: 3:46 A: 0-105 Take reading at: 3:46 A: 0-132 Take reading at: 3:46 A: 0.074 Take reading at: 3:46 A: 0.018 Take reading at: 3!46 Q15) What is the enzyme's optimum pH(s)? Answer: Q16) Use the difference between 2nd and 1st absorbance to support your conclusion for the optimum pH. Subtract Omin from 10min absorbance -0.04 0.0012 0.082 0.138 0.056 0.007
Figure 3: ● ● ● ● ● ● KDa ● 97.4 66.2 45.0 ● 31.0- 21.5 14.4 S-1 p-1 S-2 2-0 This figure was generated by centrifuging a pura sample of protein, removing the supernatant, and resuspending the pellet in the same volume as the supernatant to allow direct comparison. The supernatant and pellet samples were then prepared for SDS-PAGE identically and run via normal SDS-PAGE procedures. In the figure, "s" means supernatant and "p" means pellet. The text or number after the dash represents a different condition. For example, s-1 and p-1 are the supernatant and pellet samples under condition 1. It is not shown, but under wild-type conditions, essentially all of the protein is found in the supernatant. S-3 ● What does the intensity of each band represent? ● Would you find soluble protein in the supernatant or pellet? Why? Would you find aggregated protein in the supernatant or pellet? Why? For each condition (there are 5 different conditions), is there a higher percentage of the total protein…
100ml of LB media with 25 μg/ml of Amp and 100 μg/ml of Kan final concentration. You have 100ml of LB provided and Amp and Kan stocks at 100 mg/ml and 50 mg/ml provided. Determine how much of each antibiotic stock solution you need to add to 100ml of LB to reach desired antibiotic concentration.
##6.question. a drug is order 100mg/m2 po BID. How many milliliters will a patient receive if her BSA is 1.80m2 and concentration of solutions is 100mg/5ml?
What is the expected outcome of the ion exchange chromatography using lysozyme as outlined above? Will the protein be separated successfully or not using the materials stated in the above? Provide a brief explanation to your reasoning please answer correctly, not written assigment
Table 1 - Comparison of the effect of catechol concentration on the amount of product formed. Absorbance Potato extract Absorbance 0 mins after 30mins (2nd reading) (mL) 1st reading 1 Tube # la blank 2a 3a 4a 1 1 1 dH₂O Catechol (mL) (mL) 7 5 3 1 0 2 4 6 0.00 0.060 0.033 0-05-2 Q4) Give 2 reasons for adding dH₂O to these tubes in Table 1? Time for reading: 3:21 -0.11 Absorbance: Time for reading: 3.36 Q5) Tube la serves as a control, but why is this control needed? Absorbance: 0.197 Time for reading: 3.37 Based on the data from Table 1 answer these questions: Q1) What is the name of the enzyme found in potato extract? Answer: catechol Q2) What is the substrate? Answer: THO Q3) Name of product of this enzyme catalyzed reaction? Answer: Absorbance: 0.152 Time for reading: 3:39 Absorbance: . 166 ness Catechol Benzoquinone Subtract 1st from 2nd reading -0.01 0-137 0.11.19 0.119 Q6) Notice that your 1st absorbance reading in tubes 2a-4a are quite similar but it then becomes very different…
Gel Running Buffer is made and kept at 14X concentration for storage. We will need 1.5 L of this solution at a concentration of 1X to run our gels. How would we make this solution? I am having trouble understanding the steps to this question, if you could please help me understand it that would be greatly appreciated!
When combining 1ml of lysosome solution with a concentration of 5mg/ml and 1ml of water what is the final concentration of the lysosome solution after adding 8.0 of a biuret reagent to the solution 2.5mg/ml 1mg/ml 0.5mg/ml 5 mg/ml
Given this, if you used 6g of vitamin Z powder to make 20 ml of solution, what is the % concentration of this solution? (I gave the image since I don't know if that info is needed to solve this question.)It also gives a follow-up, if you can help here too: You work in a lab as a summer student. One of your tasks is to make sure that there is enough cell culture medium containing antibiotics to grow bacteria. One day you realize that there is only 5 ml of 10% Antibiotic stock solution in the freezer. You decide to use it all to prepare the working culture medium with 0.01% antibiotic. In the lab there is plenty of growth medium without antibiotics. (Note: dilution in medium is like dilution in water). You remember the equation to make dilutions of stock solutions. You usually use this formula to calculate the required volume of a stock solution, but you realize it can apply here as well, even though the unknown is the final volume. So, you make that dilution. Given that each bacterial…
Stock Solution: Make 10mL of 1x solution from a 2x stock solution.

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