Part 3Perform a chi-square analysis using the given data and the chi-square table of values andprobability below.Degrees offreedom12345p = 0.990.0001570.0200.1150.297Part 40.554Between 0.05 and 0.2Between 0.01 and 0.05Between 0.5 and 0.8O Between 0.2 and 0.50.950.003930.1030.3520.7111.1450.80What is the p-value from your chi-square analysis?0.06420.4461.0051.6492.3430.500.4551.3860.203.3570.051.642 3.8413.219 5.9910.016.6352.366 4.642 7.8155.989 9.4884.351 7.289 11.070 15.086No, the difference between observed and expected is likely not due to chance.Yes, the difference between observed and expected is likely due to chance.No, the difference between observed and expected is likely due to chance.Yes, the difference between observed and expected is likely not due to chance.9.21011.34513.277Assume your null hypothesis was that observed and expected are not different from each other.Can you reject the null hypothesis?

Part 4 Assume your null hypothesis was that observed and expected are not different from each other. Can you reject the null hypothesis? No, the difference between observed and expected is likely not due to chance. Yes, the difference between observed and expected is likely due to chance. No, the difference between observed and expected is likely due to chance. OYes, the difference between observed and expected is likely not due to chance.

Part 4 Assume your null hypothesis was that observed and expected are not different from each other. Can you reject the null hypothesis? No, the difference between observed and expected is likely not due to chance. Yes, the difference between observed and expected is likely due to chance. No, the difference between observed and expected is likely due to chance. OYes, the difference between observed and expected is likely not due to chance.

Biomedical Instrumentation Systems

1st Edition

ISBN:9781133478294

Author:Chatterjee

Publisher:Chatterjee

Chapter13: Artifacts And Noise In Medical Instrumentation

Section: Chapter Questions

Problem 7P

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