4) For circuit shown in Figure (3); if the voltage across the 0.5H inductance is v 100sin20t, the sinusoidal expression of the current is: a) 20sin (20t-80°) b) 10sin (20t-90°) c) 5sin (20t-30°) d) 15sin (20t-60°) L= 0.5H v = 100sin20t Figur (3)

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.7P: Let a 100V sinusoidal source be connected to a series combination of a 3 resistor, an 8 inductor,...
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4) For circuit shown in Figure (3); if the voltage across the 0.5H inductance is v 100sin20t,
the sinusoidal expression of the current is:
a) 20sin (20t-80°)
b) 10sin (20t-90°)
c) 5sin (20t-30°)
d) 15sin (20t-60°)
L= 0.5H
v = 100sin20t
Figur (3)
Transcribed Image Text:4) For circuit shown in Figure (3); if the voltage across the 0.5H inductance is v 100sin20t, the sinusoidal expression of the current is: a) 20sin (20t-80°) b) 10sin (20t-90°) c) 5sin (20t-30°) d) 15sin (20t-60°) L= 0.5H v = 100sin20t Figur (3)
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