34" C: 57 "radius 150 7. Figure P4-2
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- 3.9 The linkage in Fig. 3-10 has 0,A = 8mm, AB = 19. 3mm, AC = 13. 3mm, and offset = %3D 3. 8mm. The crank angle in the position shown is 34. 3° and ZBAC =38. 6°. Find wz, vA, VB, Vc for the position shown for w, = 15rad/s in the direction shown. ( Choose two methods) 1) Use the velocity difference graphical method. 2) Use the instantaneous center graphical method. 3) Use the analytical method. @2 B offset 02 Fig. 3-106-2 For the slider-crank mechanism shown, link (2) rotates with an angular velocity of 1.0 rad/sec CW. Assume the following link lengths: 0,0, = 10.0, O,A = 5.0, AB = BD = 5.0, O,C =15.0 cm a) For a crank angle of 0, = 60Y, draw the mechanism in the configuration closest to the one shown b) Locate all the instant centers Using the instant centers, determine: c) The angular velocity of link (3) and link (4) d) The velocity of point C on link (4); show it on the figure and write its magnitude next to it e) The velocity of point D on link (3); show it on the figure and write its magnitude next to it C 5.0 cm D `B A (4) (2) (Not necessarily drawn to scale or according to the given dimensions)((I need to solve all parts please)) For the non-offset slider crank shown in the figure below the crank O2A is rotating at constant speed of 10 rad/s CCW O2A = 70 cm, AB = 210 cm, AG3 = 100 cm. When the slider B is at its minimum position, we need to find : W2 G3 3 B 4 2 7777 The angular velocity of AB in rad/s is = Choose... + The velocity of slider B in m/s is = Choose... + The angular acceleration of AB in rad/s2 is = Choose... * The acceleration of slider B in m/s? is = Choose... + The velocity of point A in m/s (in cartesian form) is = Choose... + The acceleration of point A in m/s² (in cartesian form) is = Choose... The velocity of point G3 in m/s (in cartesian form) is = Choose... + The acceleration of point G3 in m/s² (in cartesian form) is = Choose... +
- In the mechanism shown below, points E and B have the same vertical coordinate. Find the velocities of points B. C, and D of the double-slider mechanism shown in the figure if Crank 2 rotates at 42 rad/s Ccw. And all forces acting. D EA = 0.55" AB - 2.5" AC = 1.0" 0.75" CB = 1.75" CD - 2.05" C 4 E O B 3 °2 60Task 3 Generate free body diagram for the following mechanism: C B 4 m E D m 6 m -8 m-Find out the velocity of slider D and angular velocity of CD in the mechanism shown below. Take Q1A= Q2B = 2cm; Q1Q2 = 4 cm; CD = 6 cm and wQ,A rad = 1 sec Solve using instantaneous center method. Use CCW direction. 20 QI 1 A Q2 20
- Use the planar version of Gr¨ubler's formula to determine the number of degrees of freedom of the mechanisms shown in Figure. Comment on whether your results agree with your intuition about the possible motions of these mechanisms.Solve it using complex algebra; otherwise, do not solve it. Calculate the rotational speed. theta 3' prime, and acceleration, theta 3" double prime for the mechanism in Fie 3 if theta3-50. roa=5cm and Rab= 15cm. using complex algebra method Subject: Theory of machine and mechanismDetermine the degree of freedom of the mechanism in the figure below. Then determine all the centers of the era. Then use it to find the angular velocity of link 4 as well as the sliding velocity, knowing w_2 = 10 rad /s clockwise. Note that you must specify the order and method of determining non-obvious centers. %3D PE 4 5 D. C B Link radius 2:-25mm Link radius 5:-10mm BD length: -55 and DE length=30mm its angle with a horizon of 45 degrees and also the radius of curvature of the earth at point F is equal to 20 mm. The segment AB is horizontal and BD is vertical. The contact at point Cis of the rolling type with slip and at point F the rolling is pure. 2.
- In the image on the right, there is a red gear G1 on the left with a radius of r1 = 2.81cm. Gear G1 is locked to the green gear G2 with a radius of r2 = 0.734cm. Gear G2 then shares the same axle as the blue circular saw G3, which has a radius of r3 known to make a full rotation every T = 0.836s. Using at least 6 significant digits in your calculations, compute the following: V3! 12.8cm. Gear G1 is W1 a) The angular speed wi of gear G1. Remember that angular speed is measured in radians per T3 r2 unit time. G2 b) The rim speed vi of gear G1. Since gears G1 and G2 are locked together, the rim speed of G2 is also v1. G1 G3 c) The angular speed w2 of gear G2. Since gear G2 and saw G3 share the same axle, the angular speed of G3 is also w2. d) The rim speed v3 of saw G3.The rotor in the figure turning I and II formed in the beds imbalances and their angles are saving: UI=1000 gr.mm,UII=2000 gr.mm, thetaI=45degree, thetaII=135degree. in the A and B planes to compensate for these imbalances.Find the amounts and angular positions of the masses to be subtracted from the r=100 mm radius and find the xyshow in plane.theta O = 55 The link length and value of O2 for some four bar linkage are defined below, (drive link =4.2 cm , coupler link =5.9 cm , follower link = 5.9 cm, fixed link= 6.85 cm 1. draw the linkage to scale and graphically find all possible solution (both open and cross) for 03 and O4 2. If w = 2 rad /s (CCW) find the angular velocity for bar 3 and 4 3.if a= 5 rad/s? (Ccw) find the normal and tangential acceleration for link 3 and 4