6-2 For the slider-crank mechanism shown, link (2) rotates with an angular velocity of 1.0 rad/sec CW.Assume the following link lengths:0,0, = 10.0, O,A = 5.0, AB = BD = 5.0, O,C =15.0 cma) For a crank angle of 0, = 60Y, draw the mechanism in the configuration closest to the one shownb) Locate all the instant centersUsing the instant centers, determine:c) The angular velocity of link (3) and link (4)d) The velocity of point C on link (4); show it on the figure and write its magnitude next to ite) The velocity of point D on link (3); show it on the figure and write its magnitude next to itC5.0 cmD`BA(4)(2)(Not necessarily drawn to scale or according to the given dimensions)

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Answered: or the slider-crank mechanism shown,…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question 1: The crank O1A of a mechanism as shown in figure below rotates uniformly at 955 rpm clockwise. Various links have following dimensions: OjA = 100 mm, AC = 700 mm, O3C = 200 mm, BD = 150 mm and O2D = 200 mm. Point B (Joint) is located on link AC as per figure. a) Make appropriate scale to draw position diagram using graphical method. b) Find the linear velocities (mm/sec) and angular velocities (rad/sec) for links O2D and BD and draw velocity diagram. What will be normal acceleration of Point B (Note: No need to draw Acceleration diagram) c) Identify total number of links and full joints (revolt joints) in the mechanism. 200 mm 200 mm A O2 O3 300 mm 400 mm
theta O = 55 The link length and value of O2 for some four bar linkage are defined below, (drive link =4.2 cm , coupler link =5.9 cm , follower link = 5.9 cm, fixed link= 6.85 cm 1. draw the linkage to scale and graphically find all possible solution (both open and cross) for 03 and O4 2. If w = 2 rad /s (CCW) find the angular velocity for bar 3 and 4 3.if a= 5 rad/s? (Ccw) find the normal and tangential acceleration for link 3 and 4
The linkage in the following figure has O2A = 0.8, AB = 1.93, AC = 1.33, and offset = 0.38 in. The crank angle in the position shown is 34.3° and angle BAC = 38.6°. Find a 3, A4, Ag and Ac for the position shown for 02 = 15 rad/s, a2= 10 rad/sec² in direction shown. 5. a) Using the acceleration difference graphical method b) Using an analytical method. A 3 B 02 4 1
4) Locate all the instant centers for the mechanism in Problem 2-2) @2 YA 0₂ 45° A 105⁰ 4 X Note:- • Do not provide handwritten solution. Maintain accuracy and quality in your answer. Take care of plagiarism. • Answer completely. • You will get up vote for sure.
Problem 4-6a The link lengths (a, b, c, d) and the value of 2 for a crank-rocker linkage are defined as 2, 7, 9, 6, 30°, respectively. Draw the scaled linkage. Find all possible solutions (both open and crossed) for angles 03 and 04 graphically. Орen B A LNCS 4 a GCS र 4 4" Crossed (This is not the scaled kinematic diagram.) Problem 4-7a Repeat Problem 4-6a except solve by the vector loop method.
A general inverted fourbar slider-crank linkage has links length: link 2 = a = 2, link 4 = c = 4, and link 1= d = 6 in. The input values are 02 = 60°, y = 90°. The linkage configuration and terminology are shown in figure below; note that this figure does not represent the real dimensions of the linkage We need to find the angular positions of link 4 (04), of link 3 (03) and the effective length of link 3 (b) for both open and crossed configurations. 03 Өд В 4 RB 02 02 1 02 04 Choose... For open configuration, the angle 04 measured form X axis CCW in degree = Choose... For open configuration, the angle 03 measured form X axis CCW in degree = Choose... + For open configuration, the absolute value of the effective length of link 3, b = Choose... For crossed configuration, the angle 04 measured form X axis CCW in degree = Choose... For crossed configuration, the angle 03 measured form X axis CCW in degree = Choose... For crossed configuration, the absolute value of the effective length of…
The link length and value of O2 for some four bar linkages are defined below, (fixed link =12 cm, drive link =5 cm, coupler link = 10 cm, follower link= 8 cm) 1. draw the linkage to scale and graphically find all possible solution (both open and cross) for 03 and O4, analytical . 2. If w = 2 rad /s (CCW) find the angular velocity for bar 3 and 4 3.if a= 5 rad/s² (CCW) find the normal and tangential acceleration for link 3 and 4
Problem 4-9a The link lengths and offset (a, b, c) and the value of 02 for an offset crank-slider linkage are defined as 1.4 in, 4 in, 1 in, 45°, respectively. Draw the scaled linkage and graphically find all possible solutions (both open and crossed) for angle 0z and slide position d. - slider axis B R3 A R4 offset R, 04 02 (This is not the scaled kinematic diagram.) Problem 4-10a Repeat Problem 4-9a except solve by the vector loop method.
The general linkage configuration and terminology for an offset fourbar slider-crank linkage are shown in Figure below. The link lengths and the values of 02 and w2 are defined in. For the row(s) b and c, find the velocities of the pin joints A and B and the velocity of slip at the sliding joint using an analytical method. Draw the linkage to scale and label it before setting up the equations. Link 3 Offset 04 = 90° Link 2 02 Slider position d TABLE P6-2 Data for Problems 6-6 to 6-7† Row Link 2 Link 3 Offset 02 1.4 4 1. 45 10 2 6. -3 60 -12 3 8. -30 -15
1. Find a combination of link lengths where motion of a point on output link is one quarter of a circle. 2. Find the value of all 0, 0, 0, and y in open and close configuration Read the value of link lengths and the input angle 8., then use the formulae given below to calculate the value of unknowns 03, 0, and y K₁ = = K₂= d K2 K3 = a²-b²+c²+d² 2ac A = cos 0₂ - K₁ - K₂ cos 0₂ + K3 B = -2 sin 0₂ C = K₁ (K₂ + 1) cos 02 + K3 -B± √B²-4AC 2A 0412 = 2tan-1 d K₁ = — K5 = c²d²a²-6² 2ab D = cos 0₂ - K₁ - K4 cos 0₂ + K5 E = -2 sin 0₂ FK₁+ (K₁ - 1) cos 02 +K5 0312 2 tan-1 (-E± -E± √E²4DF 2D Y = 04-03
Qestion-1: A slider-crank mechanism is shown in figure below. Position vectors for various linkages are drawn as shown in figure. Length of the rotating Link-1 (L1) is continuously changing due to the slider placed on it. Link-3 is fixed and aligned along y-axis. Note: All angles are measured anti-clockwise from x-axis and Link-1 is rotating with uniform velocity Take: L2 = 20mm, 02 =45°, L3= 30mm, o=10rad/sec, V2= 1000mm/s. a) Formulate the vector loop, position, velocity and acceleration equations b) Solve to find 01, L1, linear velocity of slider and angular acceleration of link-1. c) Identify if the mechanism can be declared as spatial or planar mechanism also identify total number of full and half joints.
According to the below figure, if the rotational velocity of link AB is constant and equal to 2 rad/s (wAB = 2rad/s), find the velocity of point E. This problem should be solved based on the concept of the 400 mm instantaneous center of rotation. Other methods are not acceptable. 700 mm 400 700 mm mm

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