200 pF 1200 pF 40 V 400 pF C4 : 600 pF Find the total capacitance for the circuit above. Just write the number; the answer is understood to be in pF.
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- Three capacitors having capacitance values of 20F,40F, and 50F are connected in parallel to a 60 - Hz power line. An ammeter indicates a circuit current of 8.6 amperes. How much current is flowing through the 40F capacitor?A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating of 600 WVDC. The capacitor and resistor are connected to a 480-V, 60-Hz circuit. Is the voltage rating of the capacitor sufficient for this connection?A resistor & a capacitor are connected in series across 230V, ac supply. The current taken by the circuit is 4 A for 50 Hz frequency. The current is reduced to 2 A, when the frequency of supply is decreased to 40 Hz. Determine the value of resistor & the capacitor.
- Let's say you measure t1/2 to be 0.037 seconds and the resistance in the circuit is 68 Ohms. Then what is the capacitance in micro Farads? Answer in micro Farads.A 50-µF and 100-µF capacitors are connected in series and across a 100 sin (wt + 30o) voltage. Write the equation of the current.a. 1.26 sin (wt + 120o) c. 5.65 sin (wt + 120o)b. 1.26 sin (wt + 90o) d. 5.65 sin (wt + 90o)sa) The voltage across a 20uF capacitance is v. = 50 sin( at - 80) volts and Frequency equal to 100 Hz. Determine the current through the capacitor i and sketch its waveform. b) Define phasor
- (iii). Determine the net capacitance C of the capacitor network shown in figure. Assume C-3 pF, C2 5 pF, C 6 pF and C 9 pl. Determine the charge on each capacitor, assun there is a potential difference of 15 V across cach network. C2 C, C3A capacitor C is connected in series with a 400 resistor across a supply of frequency 60 Hz. A current of 3 A flows and the circuit impedance is 500. Calculate: (a) the value of capacitance, C, (b) the supply voltage, (c) the phase angle between the supply voltage and current, (d) the p.d. across the resistor, and (e) the p.d. across the capacitor. Draw the Phasor diagram.A capacitor has a reactance of 40 when operated on a 50 Hz supply. Determine the value of its capacitance. In a series R–L circuit the p.d. across the resistance R is 12V and the p.d. across the inductance L is 5V. Find the supply voltage and the phase angle between current and voltage
- What is the value of capacitance if the capacitive reactance is 50 Q .Assume frequency of supply as 50 Hz ? a. 53.3x10-5 F O b. 5.3x10-5 F c. 6.36x10-5 E d. 63.3x10-5 FAt 0-, no currrent flows through the capacitors because they are open, how did you combine the capacitors for the voltage divider since it is the capacitance value and not reactance, is it right? Can we just combine the capacitance value? Please explain. I did not understand..Calculate capacitance Cand voltage U over resistance. What is the peak value of resistance's voltage? Voltage source e(t) = ésin(wt + 45°). Resistance R-50, circuit's total reactance X-50, inductance L =50mH, ê -40V and frequency f =50Hz. R L Give the answers to one decimal place. Do not write numbers in the complex number form! Absolute value of voltage source (RMS value): V Total impedance of circuit (absolute value): Capacitance: μF Absolute value of current (RMS value) supplied by voltage source: Phase angle of current: degrees Peak value of resistances voltage: 22 A