MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- According to the figure, which one is false about a normally-distributed random variable with mean M and standard deviation S? Probability of Cases in portions of the curve Standard Deviations From The Mean Cumulative % The Normal Distribution 4 -40 Values -0.0013 -2.580 -30 0.1% -1.960 -0.0214 -20 2.3% 0.1359 -10 15.9% 95% of values 99% of values 0.3413 0 50% -0.3413 +10 84.1% 0.1359 1.960 +20 97.7% 2.580 → 0.0214 1 +30 99.9% -0.0013 +40 The probability of an observation at least one standard deviation more than M is almost 15.9%. The probability of an outcome at least three standard deviations away from M is less than 1%. Almost 95% of all observations are in the interval [M- 2.58 S, M + 2.58 S]. Almost 2.3\% of observations are less than M - 2S.arrow_forwardA sample of 3 measurements are taken and recorded: a =8, y = 10 and z = 7 The sample mean is: x = = 8.33 Fill in the table below. aj (a; - x)2 Ex: 5.34 Ex: 5.34 Ex: 5.34 82 = (z-z)*+(y-a)* +(z-z) Ex: 5.34 (z-2)*+(y-z)* +(z-) = Ex: 5.34arrow_forwardWhat type of distribution is appropriate to model the number of cars driving through a certain road between 2 and 3pm on a typical day Exponential Poisson Binomial Geometric Normalarrow_forward
- E Question Help Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table Click to view page 2 of the table, 0.97 The indicated IQ score, x, is (Round to one decimal place as needed.) Enter your answer in the answer box. Save for Later O vA 12:50 esc DII @ 23 %24 96 & back 3 4 6 8 y uarrow_forwardSAMPLE 1 MEAN 5.61 MEDIAN 5.6 MODE 5.6 STANDARD ERROR 0.39992384 STANDARD DEVIATION 2.1904731 SAMPLE VARIANCE 4.79817241 KUTOSIS -0.07445435 SKEWNESS -0.69709258 RANGE 7.9 MINIMUM 1.1 MAXIMUM 9 SAMPLE COUNT 30 SUM 168.3 SAMPLE 2 MEAN 7.326666667 MEDIAN 7.3 MODE 8.7 STANDARD ERROR 0.248717785 STANDARD DEVIATION 1.362283411 SAMPLE VARIANCE 1.855816092 KUTOSIS -0.118922156 SKEWNESS -0.015286932 RANGE 5.6 MINIMUM 4.6 MAXIMUM 10.2 SAMPLE COUNT 30 SUM 219.8 AND THIS IS MY t-TEST-ASSUMING EQUAL VARIANCE Variable 1 Variable 2 Mean 5.61 7.326666667 Variance 4.798172414 1.855816092 Observations 30 30 Pooled Variance 3.326994253 Hypothesized Mean Difference 0 df 58 t Stat -3.645067529 P(T<=t) one-tail 0.000286392 t Critical one-tail 1.671552762 P(T<=t) two-tail 0.000572783 t Critical two-tail 2.001717484 IS IT RIGHT THAT MY T-STAT CAME OUT AS A NEGATIVE, AND ARE MY CALCULATIONS…arrow_forwardCompute the critical value z/2 that corresponds to a 88% level of confidence. Click here to view the standard norma distribution table (page 1D Click here to view the standard normal distribution table (page 2). Za/2 = (Round to two decimal places as needed.)arrow_forward
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