A sample of 16 items provides a sample standard deviation of 9.5. Test the following hypotheses using a = 0.05. What is your conclusion? Use both the p-value approach and the critical value approach.Ho: ²50H₂ : ² > 50Test statistic =p-value low from table=p-value high from table=X0.05 =Reject Ho if x² >- Select your answer -Hide FeedbackIncorrect(to 2 decimals)(to 3 decimals)(to 3 decimals). Use Table 11.1.(to 3 decimals). Use Table 11.1.(to 3 decimals)Hint(Hint( TABLE 11.1 Selected Values from the Chi-Square Distribution Table*Degreesof FreedomLEAST ONE THAT * *** 98882345891011121314151617181920212223242526272829304080.99 .975.000.001.020.051.115216.297484.554.8721.2391.647 2.1802.088 2.7002.558 3.2473.053 3.8163.5714.1074.6606.4087.0157.6335.229 6.2625.812 6.9087.56411.52412.198.95.8311.1451.2371.6351.690 2.16712.87813.56514.256.004.103.352.7113.9404.5754.404 5.2265.0095.8925.6296.5717.2617.9628.6728.2319.3908.907 10.1178.2609.59110.8518.897 10.283 11.5919.542 10.98212.33810.19611.689 13.09110.85612.4012.7333.325 4.168.016.211.5841.064Area in Upper Tail.90.102.7064.605 5.9916.2517.7794.8655.5786.3047.0417.7901.6102.2042.83312.017 14.06716.0133.490 13.362 15.507 17.53514.684 16.919 19.0238.5479.312Xa10.08510.86511.651Area orprobability14.84813.848 15.659.05 .0253.841 5.0247.3787.815 9.3489.488 11.1439.236 11.070 12.83215.08610.645 12.592 14.449 16.81218.47515.98718.307 20.48317.27519.675 21.92018.549 21.026 23.33719.812 22.362 24.73621.064 23.685 26.11912.44313.24014.041 30.81324.99627.48826.296 28.84527.587 30.191.016.6359.21011.34513.27722.30723.54224.76925.989 28.86931.526 34.80527.204 30.144 32.852 36.19113.120 14.611 16.47334.38213.84415.37917.29235.56314.57316.15118.114 36.741 40.11315.30816.92818.939 37.91616.04717.708 19.76820.09021.666100*Note: A more extensive table is provided as Table 3 of Appendix B (available online).23.20924.72526.21727.68829.14128.412 31.410 34.170 37.56629.615 32.671 35.479 38.93233.924 36.78140.28932.007 35.172 38.07641.63833.19636.415 39.36442.98030.57832.00033.40937.65240.64644.31438.885 41.923 45.64243.19546.96344.46148.27841.33739.087 42.557 45.72249.58814.95316.79118.493 20.59940.256 43.773 46.979 50.89251.805 55.758 59.342 63.69122.16424.43326.509 29.05137.485 40.482 43.188 46.459 74.397 79.082 83.298 88.37953.540 57.153 60.391 64.278 96.578 101.879 106.629 112.32970.065 74.222 77.929 82.358 118.498 124.342 129.561 135.807

Given n=16, s=9.5, standard deviations σ2=50

Answered: A sample of 16 items provides a sample…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Claim: The mean systolic blood pressure of all healthy adults is less than than 125 mm Hg. Sample data: For 258 healthy adults, the mean systolic blood pressure level is 124.72 mm Hg and the standard deviation is 15.18 mm Hg. The null and alternative hypotheses are Ho: μ = 125 and H₁ : µ< 125. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.)
A baseline of calibrated length 400.009 m is observed repeatedly with an EDM instrument. After 25 observations, the average of the observed distance is 400.012 m with a standard deviation of ±0.003 m. Is the distance observed significantly different from the distance calibrated at a 0.05 level of significance? Here you must write: 5.1. The two hypothesis. 5.2. The value of the test statistic. 5.3. The rejection region. 5.4. The conclusion.
A simple random sample of size n= 40 is drawn from a population. The sample mean is found to be 103.6, and the sample standard deviation is found to be 21.7. Is the population mean greater than 100 at the a =0.10 level of significance? Determine the null and alternative hypotheses. Ho: H= 100 H: u> 100 Compute the test statistic. (Round to two decimal places as needed.) %3D to Enter your answer in the answer box and then click Check Answer. Check Answer Clear All 2 parts remaining MacBook Air 10 888 F7 FS F4 F3 esc F2 FT & de 8 9 @ 2 3 4 1 P Y Q W E cab K F S > lock D
On average, Americans have lived in 4 places by the time they are 18 years old. Is this average more for college students? The 52 randomly selected college students who answered the survey question had lived in an average of 4.18 places by the time they were 18 years old. The standard deviation for the survey group was 0.5. What can be concluded at the αα = 0.05 level of significance?
I. A study reports that teenagers spend 27 hours a week online (www.telegraph.co.uk). A researcher wanted to check if this claim is true. A random sample of 200 teenagers taken showed that they spend an average of 25.7 hours per week online with a standard deviation of 8.2 hours. Perform a hypothesis test with the alternate hypothesis that teenagers spend less than 27 hours per week online. Use c = 0.05. Perform all of the steps outline in your notes and write a complete conclusion in words. Assume the distribution of hours spent online is normally distributed.
The population of heights (in inches) of students of a large university is normally distributed with mean u and standard deviation o = 4 inches. A social scientist wishes to test Ho : u 69. • State a level of significance that you think the social scientist should/could use. No need to justify your choice. • If a sample of size n = would you draw? 25 gave sample mean Xn = 70 inches what conclusion • What kind of potential error you might be making in light of your decision in part (ii)?
You wish to test the following claim (HaHa) at a significance level of α=0.001α=0.001. Ho:μ=53.4 Ha:μ<53.4You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = 45.6 39.8 42.3 45.4 33.4 46.6
Arandom sample of 15 observations taken from a population that is normally distributed produced a sample mean of 42.4 and a standard deviation of 8. Find the range for the p-value and the critical and observed values of t for each of the following tests of hypotheses using, a= 0.01 Use the distribution table to find a range for the pvalue. Round your answers for the values of decimal places. H0: mean =46 versus H1: mean<46. = <p-value <p-value t critical=t observed= b. H0: mean=46 versus H1: mean≠46 = < p-value < t critical left=t critical right=t observed=
On average, Americans have lived in 3 places by the time they are 18 years old. Is this average more for college students? The 66 randomly selected college students who answered the survey question had lived in an average of 3.1 places by the time they were 18 years old. The standard deviation for the survey group was 0.8. What can be concluded at the α = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: H0: H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is α Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest that the population mean is not significantly more than 3 at α = 0.05, so there is statistically insignificant evidence to conclude that the population mean number of places that college students lived in by the time they were 18 years old is…
Many people believe that the average number of Facebook friends is 150. The population standard deviation is 37.6. A random sample of 46 high school students in a particular county revealed that the average number of Facebook friends was 159. At =α0.01, is there sufficient evidence to conclude that the mean number of friends is greater than 150? A. State the hypotheses and identify the claim with the correct hypothesis. :H0 ▼claim or not claim :H1 ▼claim or not claimThis hypotheses test is a ▼one-tailed or two-tailed test B. Find the critical value(s) (c)Compute the test value. z= (d)Make the decision. reject or accept (e)Summarize the results. is there enough evidence to support the claim
A large milling machine produces steel rods to certain specifications. The machine is considered to be running normally if the standard deviation of the diameter of the rods is at most 0.15 millimeters. The line supervisor needs to test the machine is for normal functionality. The quality inspector takes a sample of 25 rods and finds that the sample standard deviation is 0.19. What are the null and alternative hypotheses for the test? A. H0 : σ = 0.0225 and H1 : σ ≠ 0.0225 B. H0 : σ ≥ 0.15 and H1 : σ < 0.15 C. H0 : σ2 > 0.15 and H1 : σ2 ≤ 0.15 D. H0 : σ2 ≤ 0.0225 and H1 : σ2 > 0.0225
The average scores in a pre-final examination scored by under graduate students in the previous year was 63. A tutor, after conducting the weekly tests, wishes to check whether that average has increased this year. For a sample of 70 students, the mean score was 68 with a standard deviation of 15.State the null and the alternative hypotheses. Group of answer choices H0: μ = 63 vs. Ha: μ ≥ 63 H0: μ = 63 vs. Ha: μ ≠ 63 H0: μ = 63 vs. Ha: μ ≤ 63 H0: μ = 63 vs. Ha: μ > 63 H0: μ = 63 vs. Ha: μ < 63

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