2. In a random sample of 150 drivers arrested for DUI (drunk driving), 90% were males. The 99% confidence interval for the proportion of male drunk drivers is:

According to the given information, we have Total number of drivers arrested for DUI = 150 90% were…

Answered: 2. In a random sample of 150 drivers…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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if n=20, x=43, and s=9, construct a confidence interval at a 98% confidence level, the data came from a normally distributed population.
In a survey of 1037 US adults ages 65 and over, 643 were concerned about getting the flu. A 99% confidence interval for the proportion p is?
5.A random sample of 362 married couples found that 286 had two or more personality preferences in common. In another random sample of 550 married couples, it was found that only 30 had no preferences in common. Let p1 be the population proportion of all married couples who have two or more personality preferences in common. Let p2 be the population proportion of all married couples who have no personality preferences in common. Find a 90% confidence interval for p1 – p2. (Use 3 decimal places.) lower limit upper limit
A survey of 2450 golfers showed that 281 of them are left-handed. Construct a 90% confidence interval for the proportion of golfers that are left-handed. Question 10 options: (0.104, 0.125) (0.369, 0.451) (0.100, 0.130) (0.203, 0.293)
If X=101, o=27, and n= 32, construct a 95% confidence interval estimate of the population mean, p
Suppose we wish to estimate the average number of hours per week that Americans watch TV. Use the following data from an SRS to find a 90% confidence interval: 30 64 49 40 21 58 9 43 39 43
The following data represent a random sample of five measurements from a normally distributed population: 7,4,2,5,7 a. Find 90% confidence interval for u. b. Find a 99% confidence interval for u.
Example 7. In a random selection of 64 of 600 road crossing in a town, the mean number of automobile accidents per year was found to 4.2 and the sample s.d was 0.8. Construct a 95% confidence interval for the mean number of automobile accidents per crossing per year.
In a survey of 3444 adults aged 57 through 85 years, it was found that 85.9% of them used at least one prescription medication. Complete parts (a) through (c) below. a. How many of the 3444subjects used at least one prescription medication?=2958 (this was the correct answer.) b. Construct a 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. 86.3%<p<88.1% (INCORRECT answer i got when i asked earlier) c. What do the results tell us about the proportion of college students who use at least one prescription medication? A. The results tell us that, with 90% confidence, the probability that a college student uses at least one prescription medication is in the interval found in part (b). or B. The results tell us that there is a 90% probability that the true proportion of college students who use at least one prescription medication is in the interval found in part (b). or C. The…
create a 90% confidence interval for the following data: x = 25 n = 100
The following numbers represent five randomly selected individuals’ ages: 20, 32, 36, 42, 45. If the age distribution for the whole population follows a normal distribution, which one represents the 90% confidence interval for the mean age based on this particular sample? A ) (20.26, 49.74) B ) (25.66, 44.34) C ) (14.83, 55.17) D ) (28.28, 41.72) E ) (23.72, 46.28)
In the construction of an 88% Confidence Interval for a population mean u, a has the value of

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