Suppose we observed 120 successes in a random sample of 300 subjects. What is the 98% confidence interval for p (the proportion of successes in the population)? Select one: a. (0.321, 0.456) b. (-0.456 , -0.321) c. (0.334 , 0.466) d. (-0.428, -0.372)

Suppose we observed 120 successes in a random sample of 300 subjects. What is the 98% confidence interval for p (the proportion of successes in the population)? Select one: a. (0.321, 0.456) b. (-0.456 , -0.321) c. (0.334 , 0.466) d. (-0.428, -0.372)

Related questions

Q: You wanted to know how long on average a business student at your university studies per night. You…

A: Given data is 2,1,3,2,4,1,0,3,2,4sample size(n)=10

Q: When testing for the difference between two population variances with sample sizes of n1=8 and…

Q: Click the icon to view the table. Let p; = the proportion of accidents on day i, where i = 1 for…

A: The claim is to believe that the accidents occur with equal frequency or not The null hypothesis is,…

Q: Find the indicated margin of error. Out of 330 trials, 150 turned out positive. Find the margin of…

Q: In a sample of n = 4, three subjects have scores that are 1 point below the mean each. The 4th…

Q: Find the raw score for 99% with a population mean of 29 and σ of 4

Q: If n = 220,p = 0.4,then what will be the 87.4% confidence interval for the population proportion?

Q: The width of a confidence interval for the population proportion will be: Select one: a. wider for…

Q: Dylan wants to determine a 95% confidence interval for the true proportion of high school students…

Q: find the margin of error for a sample mean, given n=16, s=4, Xbar=17. for a 95% confidence interval.

A: The margin of error for sample mean is given by,

Q: The experimental and control groups differ on the dependent measure. Which result of an inferential…

A: In the given problem, the experimental and control groups differ on the dependent measure. We have…

Q: For a sampling distribution of n = 500 and population proportion of 0.48 of those who prefer cookies…

Q: You want to see if it makes a difference which lane to be in when there is traffic. You randomly…

A: According to our policy we can answer only first three part for remaining please repost the…

Q: Find the percentile rank of students obtaining the scores:

Q: For a confidence level of 80% with a sample size of 24, find the t-score.

A: From the provided information, Confidence level = 80% Level of significance (α) = 1 – 0.80 = 0.20…

Q: The following data are the monthly salaries and the grade point averages for students who obtained a…

A: For the given data using Regression t test the hypotheses at 5% l.o.s

Q: The population mean of a set of data is unknown. The sample mean is 44, and the error bound for the…

Q: A pharmaceutical company makes tranquilizers. It is assumed that the distribution for the length of…

Q: A sample of scores has a mean of ? = 35 and ? = 6. Find the z-scores that correspond to the…

A: We have given that, Let Y be the random variable from normal distribution with mean (μ) = 35 and…

Q: Which percentile would be used to find the multiplier for 60% confidence? Select one: a. 20th…

A: Given find the multiplier for 60% confidence

Q: A national survey of 1000 adult citizens of a nation found that 19% dreaded Valentine's Day. The…

Q: If n = 330 and X = 264, construct a 95% confidence interval for the population proportion, p.

A: Ans#- From the provided information, Confidence level = 95% Sample size (n) = 330, x = 264 Sample…

Q: The line of best fit through a set of data is y = 25.662 + 2.005x According to this equation, what…

Q: What percentage of scores fall between the following z scores: -1 to +1; -1 to +2; and -1 to +3?

A: a) -1 to +1 = P(-1<z<1) = P(Z<1)-P(Z<-1) =0.8413-0.1587 =0.6826 =68.26%

Q: Construct the confidence interval for the population mean . C=0.98, x=15.3, = 10.0, and n=75

A: The Confidence Interval formula is X ± Z s √(n) Where: X is the mean Z is the Z-value…

Q: How large is the sample if the confidence level is 97%, Ɛ = 2.5% and ρ = .35?

Q: A doctor is concerned that a drug treatment causes people to run a fever. She recruited n = 50…

A: Given Data: n=50 There is only one sample

Q: It is thought that 12% of all students taking a particular course received a grade of A. In a sample…

Q: FIND t a n = 15 for the 98% confidence interval for the mean.

A: Provided information that, n=15 Alpha (α)=1-0.98=0.02 α/2=0.01

Q: Would you favor spending more federal tax money on the arts? Of a random sample of n1 = 236 women,…

A: From the provided information,

Q: Suppose you calculate a 95% confidence interval for a proportion to to be: 0.39 to 0.78. Determine…

A: Given, Lower bound = 0.39 Upper bound = 0.78 Here, we use to determine the margin of error.

Q: At OC, students have been surveyed to see whether they attend orientation. The data is as follows:…

A: Woman Men Yes 162 112 No 148…

Q: If X= 102, o=9, and n=63, construct a 95% confidence interval estimate of the population mean, μ.

A: Formula to constructing the confidence interval about mean , when the population standard deviation…

Q: You have been hired by a consortium of local car dealers to conduct a survey about the purchases of…

A: Given: Confidence level = 95% Margin of error = 0.03 Formula Used: n = ZαMargin of error2 p(1-p)

Q: In a fishing lodge brochure, the lodge advertises that 75% of its guests catch northern pike over 20…

A: Given that, In a fishing lodge brochure, the lodge advertises that 75% of its guests catch northern…

Q: If X=72, σ=13, and n=66, construct a 95% confidence interval estimate of the population…

Q: Your state is considering raising the legal age for consumption of alcoholic beverages to 21 years…

A: p = 0.5 Margin of error = 0.01

Q: Determine tc for n = 15 and a confidence level of 99%.

A: From the given information, Sample size (n) =15, Confidence level (1-α)= 0.99 Thus, the t-critical…

Q: You have 16 vampire bats. These bats have a population variance of 3.4 ounces. You wish to make a…

A: Given: Sample size (n) = 16 Population variance σ2=3.4 Sample mean x¯=15.20 Confidence level = 0.950

Q: For a sampling distribution of n = 800 and population proportion of 0.42 of those who prefer cookies…

A: We have find distribution...

Q: If n = 440 and X = 352, construct a 90% confidence interval for the population proportion, p. Give…

Q: A professor believes that his math students have different IQ than the average college students. He…

A: Given that, The random variable X is normally distributed. And sample size is 30=~ infinite so we…

Question

Suppose we observed 120 successes in a random sample of 300 subjects. What is the 98% confidence interval for p (the proportion of successes in the population)?

Select one:

(0.321, 0.456)

(-0.456 , -0.321)

(0.334 , 0.466)

(-0.428, -0.372)

Expert Solution