MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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Suppose we wish to estimate the average number of hours per week that Americans watch TV. Use the following data from an SRS to find a 90% confidence interval:
30 64 49 40 21 58 9 43 39 43
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- Suppose that a health expert has claimed that 28% of college students smoke cigarettes. To investigate this claim, researchers survey a random sample of college students. Using this sample, a 95% confidence interval for the percentage of college students who smoke is found to be 19% to 24%. On the basis of this interval, explain whether the claim that 28% of all college students smoke is reasonable or not. You may need to use the appropriate table in the Appendix of Tables to answer this question. a) The claim of 28% is reasonable because the value 28% is not in the confidence interval. b) The claim of 28% is not reasonable because the value 28% is in the confidence interval. c) The claim of 28% is not reasonable because the value 28% is not in the confidence interval. d) The claim of 28% is reasonable because the value 28% is in the confidence interval.arrow_forwardA learn-to-type software program claims that it can improve your typing skills. To test the claim and possibly help yourself out, you and five of your friends decide to try the program and see what happens. Use the table below to construct a 99% confidence interval for the true mean change in the typing speeds for people who have completed the typing program. Let Population 1 be the typing speed before taking the program and Population 2 be the typing speed after taking the program. Round the endpoints of the interval to one decimal place, if necessary. Typing Speeds (in Words per Minute) Before After 52 47 44 42 40 46 50 43 46 34 38 50 Lower end point upper end pointarrow_forwardIn a random sample of 145 students, we find that 53% have attended a baseball game at some point in their college careers. Construct a 95% confidence interval with a confidence interval of .53.arrow_forward
- According to a recent study only 34% of adults in the United States could name all three branches of government. This was based on a survey given to a random sample of 1750 adults. Calculate a 95% confidence interval (z score=1.96) for the proportion of all U.S. adults who could name all three branches of government. SHOW YOUR WORK, no work=no creditarrow_forwardYou are going to construct a 99% confidence interval for the proportion ofhip replacement recipients who require follow up physical or occupationaltherapy. You want the margin of error to be .045. Your initial guess is that72% of the population requires follow up physical or occupational therapy.What should the sample size be to achieve this margin of error?arrow_forwardIf 64% of a sample of 550 people leaving a shopping mall claims to have spent over $25 create and interpret a 95% confidence interval estimate for the proportion of shopping mall customers who spend over $25arrow_forward
- A survey of credit card holders revealed that Americans carried an average credit card balance of $3900 in 1995 and $3300 in 1994 (U.S. News & World Report, January 1, 1996). Suppose that these averages are based on random samples of 400 credit card holders in 1995 and 450 credit card holders in 1994 and that the population standard deviations of the balances were $880 in 1995 and $810 in 1994. Construct a 95% confidence interval for the difference between the mean credit card balances for all credit card holders in 1995 and 1994. a. ($285.81, $414.19) b. ($435.81, $700.19) c. ($845.81, $9984.19) d. ($485.81, $714.19)arrow_forwardThe figure to the right shows the results of a survey in which 997 adults from Country A, 1022 adults from Country B, 1013 adults from Country C, 1011 adults from Country D, and 1008 adults from Country E were asked whether national identity is strongly tied to birthplace. Construct a 95%confidence interval for the population proportion of adults who say national identity is strongly tied to birthplace for each country listed. The 95% confidence interval for the proportion of adults from Country A who say national identity is strongly tied to birthplace is ,. (Round to three decimal places as needed.) Country A 37% Country B 18% Country C 27% Country D 46% Country E 11 %arrow_forwardListed below are the amounts of net worth (in millions of dollars) of the ten wealthiest celebrities in a country. Construct a 95% confidence interval. What does the result tell us about the population of all celebrities? Do the data appear to be from a normally distributed population as required? 250 194 192 174 166 155 146 146 146 141arrow_forward
- What Z score would be used to construct a 90% confidence level? Is it ... a. 1.65 b. 2.33 c. 2.58 d. 1.96arrow_forwardA Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages. Construct a 95% confidence interval for the proportion of adults who have a Facebook page.arrow_forwardIn your local high school, a random sample of 10 high school seniors participated in a course to increase their knowledge of healthy living activities. The students were given a knowledge quiz before and after the program. The scores are listed below. Calculate a two-sided 95% confidence interval for the mean difference in the scores. Give an interpretation of the confidence interval. You MUST show your work Student Before After 1 65 70 2 55 71 3 72 68 4 49 65 5 71 89 6 89 95 7 90 99 8 85 82 9 75 84 10 78 76arrow_forward
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