Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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- Given the following circuit below, at t=0 the switch closes: + Vs R₁ m Vs = 9V R₁ Ry = 10kΩ Xt=0 R2 i(t) R₂ = 5kN C C = 200μF (a) Use the differential equation method to determine the output currentarrow_forwardThe values of the elements of an RLC circuit are given. Solve the initial value problem with the given impressed voltage e(t). di + Ri + dt i(t)dt = e(t), i(0) = 0 L=1, R= 50, C = 1.6x 10; e(t) = 20t if 0st<5, e(t) = 0 if t2 5 Click the icon to view a short table of Laplace transforms. Solve the initial value problem. i(t) =arrow_forwardFind vC(t) and iL(t) for the circuit below and plot both waveforms for t = -1 s to t = 5 sarrow_forward
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- - Determine which of the following function are (even, odd or not) function: 1- f(t) = 3t2 sin(3t) %3D 2 - f(t) = 4t3 + 6 sin(2t) %3D 3 - f(t) = t² sin(2t) cos(3t) f(t) = 2 sin(t²) 4 - 5 - f(t) = t2 + 4 cos (2t) +3 sin(2t)arrow_forwardQ2) Sketch the following waveforms a) V:(t) = Su(t+2) + 8u(t) - 6u(t-4) b) V2(t) = 50e 200 c) V:(t) = r(t+4) – r(t-3)arrow_forwardDifferential equations Find the steady-state current in an LRC circuit when L = 1/2h , R = 20Ω, C = 0.001f and E(t) = 100sen60t+200cos40t V. Dont skip steps plsarrow_forward
- A second order circuit's impulse and step response The figure below shows a series second order RLC circuit. The system input is a step voltage source vin(t) = u(t) and the output is the voltage across resistor R. + Vin(t) C m L i(t). RVout (t) Series RLC As shown in the section regarding second order LCCDES impulse response, the Kirchhoff's voltage law equation can be written as di ½ i(t)dt + L + Ri = vix(t) = u(t). di Differentiating results: + di² Ldt LC d²i Rdi 1 + i= =(t). The circuit's characteristic equation can be written as: = 0. R + = + s+ L LC A system's impulse response can be found using the residue function. Ex: for the LCCDE b₂ d²v + b₁ dy b₁1/4 + bo= αι +ao, dx di [R, P] = residue ([a1 a0], [b2 b1 b0]) Vectors [a1 a0] and [b2 b1 b0] are the input (right hand side) and output (left hand side) coefficients respectively. Vector R contains the residues and vector P contains the roots (poles) of the characteristic equation. If the impulse response has the form h(t) = Aet +…arrow_forwardplease do all partsarrow_forwardFind the relationship between the output v. (t) and inputs v, (t) and v, (t). R5 C R4 V2 0- R2 Vo v1 R1 R3arrow_forward
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