1. What are the phase angles between the two sine waves in parts (a) and (b) of fig. shown below. B 0° 45° 90° 135° -30°/0° (a) (b)

Terms: amplitude (A), phase angle (p), frequency (f), angular frequency (w), period (T), peak value (Vp), peak-to-peak value (Vpp). Draw a 60 Hz, 5 Vp sine wave on a coordinate axis and graphically identify as many of the terms as possible from the previous section. Use voltage in volts for the y-axis, and time in milliseconds for the x-axis. You can use the blank OSC templates shown in the procedure section to draw the signals. Expert Solution Vp 5 Volls f = 60H₂ Time period (T) = '/f angular frequency (W) = 2πTf =2 TT (60) = ㅗ seconds 60 Amplitude (A) = 5 volts, Vp = 5 = vp milli seconds below plot) peak to Peak Value (UPP) = 2 Vp=2 (5) = 10, volts Phase we can't find. E didn't mention about horizontal axis shifting] T 377 rad/see. Upp PA TA 25/3 50% 5 volts, (from 25 100 t (ms)

A voltage wave of 250 kHz has a Vmax-5 V and Vmin=-35 V. The duty cycle of this wave is 0.875. This voltage waveform has been applied across a 2.5 µH inductor for a very long time so that steady state has been achieved. Diagrams of the wave parameters and circuit are shown in this figure: L What is the average voltage of this wave? Average voltage = 35 V Voltage (arb, unit) 1.25 Minimum current: -3.5€ Amps 1 0.75 0.5 0.25 0 4.25 05 Have you integrated the wave over full cycle? 4.75 4 -1.25 Vmax 0.5 Vmin What is the average current flowing through the inductor? Average current = 3.56 A 15 Period/s On average, there is no power consumed by the inductor. Have you considered this? What are the maximum and minimum currents that flow through the inductor? Maximum current: 0.50 Amps D= 25 TH TH Have you used the relationship for current and voltage in an inductor? Have you considered the slope of the current wave?

From the information in the table below, draw on graph paper the sine wave, square wave, and triangle wave