1. Construct the potential-pH (Pourbaix) diagram for zinc using the following reactions and assuming the activity of all dissolved substances (i.e. any metal cations or anions) is 106. Label the stable species in each region. Designate regions as Active (Corrosion), Passive, or Immune. Ranges for potential -2.5 VSHE to +2 VSHE (Y-axis) and for pH -2 to 14 (X-axis) while plotting the results. {1} Zn²++2e−=Zn(s) (E。= -0.764 V vs.SHE) {2} ZnO(s)+2H++2e¯¯=Zn(s)+H₂O (E。=-0.439 V vs.SHE) {3} ZnO2+4H+2e¯=Zn(s)+ 2H2O (E0= +0.441V) {4}Zn²++H20=Zn0+2H+ (equilibrium constant = 3.16 X 10-³) {5} ZnO+H20=ZnO₂²+2H+ (equilibrium constant = 1.58 X 10-30)
1. Construct the potential-pH (Pourbaix) diagram for zinc using the following reactions and assuming the activity of all dissolved substances (i.e. any metal cations or anions) is 106. Label the stable species in each region. Designate regions as Active (Corrosion), Passive, or Immune. Ranges for potential -2.5 VSHE to +2 VSHE (Y-axis) and for pH -2 to 14 (X-axis) while plotting the results. {1} Zn²++2e−=Zn(s) (E。= -0.764 V vs.SHE) {2} ZnO(s)+2H++2e¯¯=Zn(s)+H₂O (E。=-0.439 V vs.SHE) {3} ZnO2+4H+2e¯=Zn(s)+ 2H2O (E0= +0.441V) {4}Zn²++H20=Zn0+2H+ (equilibrium constant = 3.16 X 10-³) {5} ZnO+H20=ZnO₂²+2H+ (equilibrium constant = 1.58 X 10-30)
Chapter21: Potentiometry
Section: Chapter Questions
Problem 21.26QAP
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Transcribed Image Text:1. Construct the potential-pH (Pourbaix) diagram for zinc using the following reactions and
assuming the activity of all dissolved substances (i.e. any metal cations or anions) is 106. Label
the stable species in each region. Designate regions as Active (Corrosion), Passive, or Immune.
Ranges for potential -2.5 VSHE to +2 VSHE (Y-axis) and for pH -2 to 14 (X-axis) while plotting
the results.
{1} Zn²++2e−=Zn(s) (E。= -0.764 V vs.SHE)
{2} ZnO(s)+2H++2e¯¯=Zn(s)+H₂O (E。=-0.439 V vs.SHE)
{3} ZnO2+4H+2e¯=Zn(s)+ 2H2O (E0= +0.441V)
{4}Zn²++H20=Zn0+2H+ (equilibrium constant = 3.16 X 10-³)
{5} ZnO+H20=ZnO₂²+2H+ (equilibrium constant = 1.58 X 10-30)
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