Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN: 9781305079113
Author: David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher: Cengage Learning
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1. Construct the potential-pH (Pourbaix) diagram for zinc using the following reactions and
assuming the activity of all dissolved substances (i.e. any metal cations or anions) is 106. Label
the stable species in each region. Designate regions as Active (Corrosion), Passive, or Immune.
Ranges for potential -2.5 VSHE to +2 VSHE (Y-axis) and for pH -2 to 14 (X-axis) while plotting
the results.
{1} Zn²++2e−=Zn(s) (E。= -0.764 V vs.SHE)
{2} ZnO(s)+2H++2e¯¯=Zn(s)+H₂O (E。=-0.439 V vs.SHE)
{3} ZnO2+4H+2e¯=Zn(s)+ 2H2O (E0= +0.441V)
{4}Zn²++H20=Zn0+2H+ (equilibrium constant = 3.16 X 10-³)
{5} ZnO+H20=ZnO₂²+2H+ (equilibrium constant = 1.58 X 10-30)
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Transcribed Image Text:1. Construct the potential-pH (Pourbaix) diagram for zinc using the following reactions and assuming the activity of all dissolved substances (i.e. any metal cations or anions) is 106. Label the stable species in each region. Designate regions as Active (Corrosion), Passive, or Immune. Ranges for potential -2.5 VSHE to +2 VSHE (Y-axis) and for pH -2 to 14 (X-axis) while plotting the results. {1} Zn²++2e−=Zn(s) (E。= -0.764 V vs.SHE) {2} ZnO(s)+2H++2e¯¯=Zn(s)+H₂O (E。=-0.439 V vs.SHE) {3} ZnO2+4H+2e¯=Zn(s)+ 2H2O (E0= +0.441V) {4}Zn²++H20=Zn0+2H+ (equilibrium constant = 3.16 X 10-³) {5} ZnO+H20=ZnO₂²+2H+ (equilibrium constant = 1.58 X 10-30)
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