Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- 5arrow_forward1. Clostridium butyricum does not appear to have superoxide dismutase (SOD) and catalase enzymes. How would the growth of C. butyricum in oxic conditions compare to its growth in anoxic conditions? On this basis, what is the aerotolerance category of C. butyricum? 2. Citrobacter freundii is a facultatively anaerobic bacterium. Why would you expect this bacterium to grow better (i.e. form larger colonies) in an oxic environment than in an anoxic one? (as a hint, do some research on the “Pasteur effect”)arrow_forwardYour roommate left the deviled eggs out on the counter for 8 hours, but is happily eating them for breakfast. "We learned that bacteria take 20 minutes to reproduce at room temperature," he explains, "so I figure at most there's only a couple hundred in there. No big deal." What is your response, after remembering the equation N Noert, and the fact that e is roughly equal to 2.72? %3D O The intrinsic rate of increase (r) is only equal to 2, since each bacterium divides in half. No big deal. Hand me a fork! O If just 1 dangerous bacterium landed on your egg at the beginning of the night, there would now be approximately 1.7 million. They have been growing exponentially all night! You might be okay, but better not risk it. O If just 1 dangerous bacterium landed on your egg at the beginning of the night, there would now be nearly 27 billion. They have been growing exponentially all night! Call me if you need a ride to the hospital later. So the population only doubled 3 times for every…arrow_forward
- For any antibiotic compounds that don’t appear to inhibit translation of proteins from the ribosome, purpose another potential mechanism whereby this class of antibiotic might be able to act (outside of cell wall/membrane formation). Explain in deatil.arrow_forward2) We often think only of DNA and RNA as nucleic acids. Discuss the role of other, less “well-known” nucleic acids, such as cAMP, cGMP, NADH, NADPH, and FADH.arrow_forwardWhat does it mean to say that a cell is “competent” and how is this relevant to natural bacterial transformations?arrow_forward
- Consider a polymeric membrane within a 6 cm diameter stirred ultrafiltration cell. The mem- brane is 30 μm thick. The membrane has pores equivalent in size to a spherical molecule with a molecular weight of 100,000, a porosity of 80%, and a tortuosity of 2.5. On the feed side of the membrane, we have a solution containing a protein at a concentration of 8 g L−1 with these properties: a = 3 nm and DAB = 6.0 × 10−7 cm2 s−1. The solution viscosity is 1 cP. The hydrody- namic pressure on the protein side of the membrane is 20 pounds per square inch (psi) higher than on the filtrate side of the membrane. Determine the convective flow rate of the solution across the membrane and the rate at which the protein crosses the membrane. The solution on the feed side of the membrane is being stirred at 900 RPM.arrow_forward.The image below shows the growth rate vs temperature profiles of two strains of bacteria. They differ only in their ability to regulate membrane fluidity. Which of the following is the most likely explanation for the data shown? Growth Rate A B 10 20 30 40 Growth Temperature (°C) A. At 35°C, the abundance of saturated fatty acids is probably similar in the two strains. B. Strain B likely has a mutation that results in constitutive (constant) desaturase expression. C. At 20°C, membrane fluidity is lower in strain A than strain B. D. Strain A has a mutation that results in no desaturase expression.arrow_forwardI mutated carboxylic anhydrase enzyme active site residue. For example, Histidine 64 and valine 121. How would you test the function of the mutants?arrow_forward
- Your lab is determining the oxygen growth requirements of several different bacteria. For this experiment you'll need 40 tubes of thioglycolate broth. The formula on the bottle says to mix 23.8 g of powdered broth with 1 liter of deionized water. Assuming 7 mL of broth per tube. How many grams of powdered broth will be required for this experiment? (Show your answer to 3 decimal places)arrow_forwardat punctures the bacterial cell wall has just been recently isolated from the F the peptide reveals the following information below: IOTE: when the sequence is nat knawn, a comma separates the amino acids) Hydrazine Acid Hydrolysis (6 N HCI) at 110 °C Heptapeptide (2) Arg, Pro, Phe, Tyr, Ala, Lys 2.4-dinitrofluorobenzene DNP-Phe Lys and modified free Peptide 1 (Ala, Lys) amino acids Cleovoge with Trypsin, then chromatography Peptide 2 (Pro, Arg, Tyr) Peptide 3 (Phe, Arg) Phe Cleavage with Chymotrypsin, then chromatography Peptide 4 (Arg, Tyr) Peptide 5 (Lys, Pro, Ala, Arg) When answering the questions below, please use the ONE-LETTER CODE for the amino acid, with NO spaces and symbols between each letter. 1. What is the C-terminal residue? K 2. What is the N-terminal residue? F 3. What is the sequence of Peptide 3? GP 4. What is the sequence of Peptide 5? LPAA 5. What is the averall amino acid sequence? ALarrow_forward8. Which of the following is NOT true about polypeptides? The peptide bond that links the amino acids together is a type of covalent bond formed through dehydration synthesis. If the overall isoelectric charge of a polypeptide is negative, it will be pulled towards the cathode end during gel electrophoresis. The polypeptide chain modified with ubiquitin molecules are tagged for proteasomal degradation ○ In prokaryotic translation, the initial polypeptide chain produced has a formylmethionine amino acid at the N- terminal.arrow_forward
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