0.1 0.2 0.6 Normalized Intensity 0.3 0.4 0.5 -7.26 0.9 1.0 0.8 10 0.7 7.24 -7.18 7.06 -7.04 8 6 3 2 1 Се -5.03 -5.01 4.99 -2.51-2.40 -2.38 0.84 -0. 0.77 0.80 0.76 0.78 1.78 1.76 1.43 1.24 1.24 1.22 1.20 1.20 0.85 0 0.00 0.100.13 0.05 0.01 0.11 0.00 0.00 0.20 1.39 0.01 ㅂ الا ㅂ 7.5 7.0 6.5 6.0 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 1.5 1.0 0.5 0 -0.5 Chemical Shift (ppm) No. (ppm) Value Absolute Value Non-Negative Value 1 0099.. 0.010.00694299 2.51107248e+8 0.00694299 2 5985.. 1.621.39106357 5.03106437e+10 1.39106357 3 7131.. 1.860.19860779 7.18305434e+9 0.19860779 4 0945. 2.090.00139688 5.05211080e+7 0.00139688 5 2777.. 2.310.00216320 7.82363760e+7 0.00216320 6 3260.. 2.480.11244215 4.06669901e+9 0.11244215 7 5085.. 2.530.00594537 2.15026496e+8 0.00594537 8 9855.. 5.050.04605456 1.66565670e+9 0.04605456 9 9538.. 7.180.12837733 4.64302746e+9 0.12837733 10 2198.. 7.330.09553453 3.45520026e+9 0.09553453 11 7899.. 7.820.00341729 1.23593264e+8 0.00341729 -2.09 1.80 0.75 0.00

Apply the Q test to the following data sets to determine whether the outlying result should be retained or rejected at the 95% confidence level. a. 85.10, 84.62, 84.70b. 85.10, 84.62, 84.65, 84.70

Molar concentration of the dye stock solution: 2.52e-5 mol/L Operating Wavelength: 630 nm Solutions(Dilutions) Absorbance (A)(a.u.) 1 0.073 2 0.118 3 0.258 4 0.477 Using linear regression determine the absorbance/concentration relationship for the dye. [dye] =_____  x A

THE Y-INTERCEPT FOR THE FOLLOWING GRAPH IS: -35.0 In K# -10749 -27 -35.2 -35.4 -35.6 -35.8 -36.0 -36.2 7.4 In K = -AH/RT+AS*/R In K* = -10,749/T-27 R² = 0.974 7.6 7.8 974 NOT ENOUGH INFORMATION 8.2 8.0 (1/7)/10-4K-1 8.4 8.6

Please create a caption for this table.  Solution NaCl Conc. (%) Osmolality (mOsm)  % transmittance Absorbance % hemolysis % crenation C distilled  0 0 0.001029 4.987584625 100 0.03354 1 0.177179111 54.61 0.001551 4.809388202 96.42720001 0.05837 2 0.297126222 91.58 0.01012 3.994819487 80.09527231 0.08444 3 0.442542222 136.4 3.849 1.414652089 28.3634704 0.134 4 0.590164444 181.9 64.8 0.188424994 3.777880643 0.2125 5 0.74752 230.4 95.64 0.019360433 0.388172513 0.3368 6 0.89644 276.3 99.56 0.001915112 0.038397585 0.5336 7 1.095648889 337.7 99.98 8.68676E-05 0.001741676 0.9834 8 1.336711111 412 100 0 0 2.1 9 1.755568889 541.1 100 0 0 7.9 10 2.674395556 824.3 100 0 0 57.83 11 4.490211111 1384 100 0 0 99.72

20,18,2,4,15,15,10 Using these data, construct a 80% confidence interval for the average net change in a student's score after completing the course. Assume the population is approximately normal.  Construct the 80% confidence interval. Round your answer to one decimal place.

Learning AA prod03-cnow-owl.cengagenow.com Login Learning Learning × Online tea... y dr. marlow... ember L... with We 3. AS surroundi... M 2BrF3 (9) Br2 (g) + 3F2 (9) 4. AG° = AH°... M 5. AG: Pre... 1req 6. AG: Enthal... Using standard thermodynamic data at 298 K, calculate the free energy change when 2.14 moles of BrF3 (9) react at standard conditions. Substance AG (kJ/mol) 7. AG fro... 1req Question Question Question 8. Calculat... 1req AG° = 9. Calculat... 1req BrF3 (9) -229.4 Br2(g) 3.1 F2(9) 0.0 kj

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ALEKS - Jacqueline Hoppenrey x G convert mg to g - Google Searc x A www-awn.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IQiHqRdYV 6Ux63Syp.JXz0Coxvwqgg4JkWI72X79QvOLp9_7U27sYQhkaocvdwecGvsUzo65uy3F6spORRg1XSqgh81is O STOICHIOMETRY Using molarity to find solute mass and solution volume Jacqueline A chemist adds 55.0 mL of a 4.75M silver perchlorate (AGCIO,) solution to a reaction flask. Calculate the mass in grams of silver perchlorate the chemist has added to the flask. Round your answer to 3 significant digits. Explanation Check Privacy Accessibil 2021 McGraw-Hill Education All Rights Reserved Terms of Use

Where am I going wrong?   The collision cross section for neon is 0.24 nm2.Calculate the mean free path (in nanometers), between collisions for neon atoms at a pressure of 1.00 atm and a temperature of 31°C.    λ = _______ nm.