Designing And Performing A Procedure

(.1063 KIO31) (1 mol KIO214 g) x 6 mol S2O41 mol KIO= .00298.04150= .259 M

Using elemental analysis to determine the percent mass composition of each element in a compound is the first step in creating an empirical formula. There are many different types of elemental analysis, but in this experiment gravitational analysis and Beer’s Law are used. Elemental analysis is first used to find the moles of each element, then converted to mass, and then the percent mass of the element in the product is found (2).

Weight the mass for the different percent of zinc and copper mixtures, which have 11 groups.

m = mass of water = density x volume = 1 x 26 = 26 grams

The purpose of this lab is to determine the formula of an unknown hydrate. To achieve this, we heated a hydrate over a Bunsen burner to drive out the water. As a result, the anhydrate is left and the data is used to calculate the mole ratio between the amount of anhydride and water. Then the mole ratios are used to calculate the hydration number, which was 4.8, but was rounded to 5 in the formula. The accepted formula is 〖CuSO〗_4∙5H_2 O and the percent of error was 4%.

1. Label each substance on seven pieces of paper. Put two pieces of magnesium ribbon on the paper labeled “Magnesium”.

The goal of this experiment was to determine the empirical formula for a hydrate of magnesium sulfate and water. The technique that was used was measure the mass of the hydrate and then apply heat to evaporate the water. Then determine the mass of water that was in the hydrate and the mass of the remaining magnesium sulfate. The equation for the hydrate is determined by calculating the mole to mole ratio of the water and the anhydrous. The resulting formula will be formated as: MgSO4*_H2O

Mol of Cu = 0.043866 mol CuSO4 * 1 mol Cu1 mol CuSO4 = 0.043866 mol [IV]

Part 1: MULTIPLE CHOICE (48 points). Choose the one alternative that best completes the statement or answers the question. Record your answer on the scantron. Each question is worth 3 points. 1) A student weighed 30.00 µg of sulfur in the lab. This is the same mass as A) 3.000 × 10 4 ng. B) 3.000 × 10 -5 mg. C) 3.000 × 10 -8 g. D) 3.000 × 10 -5 kg. 2) 1)

Based on my and other classmates' observations and results it can be proved that every time magnesium combines with oxygen to form Magnesium oxide the percent composition for magnesium will be 60.31% and for oxygen it will be 30.69 % (the results achieved by experiments are

Molar Mass is basically in grams per mole for example salt has a molar mass of 5.8g per mole. The mass of an element refers to 6.0221415x1023 molecules of the substance. Molar Mass helps us figure out how many grams per mole we need to do this project and it helps us know how much we need to put into the solution. If you don’t Find

) Suppose that some magnesium oxide smoke had escaped during the investigation, the Mg:O ratio would have increased from 58% to 72%. The final mass of MgO would have decreased because the magnesium oxide smoke is part of the product and when some of it escapes, it decreases the final mass.

2. Calculate the mass of the reaction mixture in each reaction first by determining the volume of the solution and then assuming that the density of the solution is the same as pure water (1.0g/ml). Show work here and record your answer in Data Table 2.

If the mass of the reactants are compared to the mass of the products, then the mass will stay the same because the law of conservation of mass states that in any given chemical reaction, the total mass of the reactants equals the total mass of the products.

In practice, the molecular mass (M), of a compound is the sum of the atomic masses (atomic weights) of the atoms as given in the molecular formula. For instance, the Molecular Mass (M) of the compound carbon dioxide is