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Mg-O Ratios Lab

Decent Essays

) Suppose that some magnesium oxide smoke had escaped during the investigation, the Mg:O ratio would have increased from 58% to 72%. The final mass of MgO would have decreased because the magnesium oxide smoke is part of the product and when some of it escapes, it decreases the final mass.

Calculation:
What should have happened:
Mg= 0.18 g
MgO= 0.31 g
O= 0.13 g
%Mg = (mass Mg / mass MgO)(100) = (0.18 g / 0.31 g) (100) = 58% Mg
But we lost MgO as smoke…
What actually happened:
Mg= 0.18 g
MgO= 0.25 g
O= 0.07 g
%Mg = (mass Mg / mass MgO) (100) = (0.18 g / 0.25 g) (100) = 72% Mg
b) If all the magnesium in the crucible had not burned, the …show more content…

This affected the values shown on the balance resulting as rounding off in the machine and giving us inaccurate numbers to work with when making calculations and causing a small percentage error.

2. The second source of error in the lab is when opening the lid of the crucible which allowed smoke of magnesium oxide to escape. During the lab, we removed the lid a couple of times to allow oxygen to enter the crucible so the magnesium reacts with the air to form magnesium oxide. However, the smoke could have easily escaped from the crucible because of the strong force of heat from the laboratory burner. This could have affected the lab results by decreasing the final mass when some of the product have escaped.

3. The third source of error is not knowing for how long to exactly heat the magnesium until it no longer ignites and forms into a white powder of magnesium oxide. In the procedure, it is stated for how long to heat the magnesium, but as the lab went on, it is realized that the magnesium had to be heated for a longer time. This could mean that the magnesium could have been not heated long enough or too little for it to be fully converted into the magnesium oxide product effecting the final results of the lab by having smaller

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