Deborah Bell
April 17, 2012
Chemistry 1212K Lab Synthesis Report
Introduction In this Chemistry Lab the main objective is to perform accurate chemical analysis for the quantity of elements and compounds in a sample. There will be a compound made then synthesized. The methods used were acid-base titrations, redox titrations, gravity filtration, and distillation. General conclusions included
Procedures
Weight of Crucibles
1. The first experiment is Preparation of a Cobalt Amine Bromide Product ; Synthesis #3 was used to create the compound. Added 5 grams of cobalt carbonate to 20 mL of hrdrobromic acid in a beaker. Noticied a slight color change to dark purple. Solution frothed after it settled I mixed in 15mL water and
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Procedure for Preparation and Standarization of 0.1M Na2S2O3 KIO3 + 6 HCl + 6 Na2S2O3 → 3 Na2S4O6 + KI +3 H2o + 6 NaCl
All standardizations are performed in triplicate. Weigh out .1000-.1200 gram KIO3. Add 70-80 mL of deionized water. Swirl and dissolve. Add 3 mL of 6M HCl. Swirl and mix. Quickly titrated the brow-red solution with 0.1M Na2S2O3 until it is light yellow. Then add 3.5 mL of starch indicator. Titrate again until the dark color first disappears.
My results yielded a high Average Molarity .270M . The ideal would be around 1.000M . Deviation was ± 1.20
Trial 1: (.1063 KIO31) (1 mol KIO214 g) x 6 mol S2O41 mol KIO= .00298.04150= .259 M
Trial 2:
.110 KIO311 mol KIO3214 gx 6 mol1 mol= .290 M
Trial 3:
.1047 g KIO311 mol KIO3214 gx 6 mol1 mol= .261 M | Initial vol | Final vol | total | Trial 1 | 7.21 | 18.42 | 11.21 | Trial 2 | 5.57 | 16.18 | 0.61 | Trial 3 | 7.43 | 18.93 | 11.50 |
6. Procedure for Analysis of % Co3 using standardized 0.1M Thiosulfate 2 Co (NH3)4Cl3 + 2 S2O3 → 2 Co + S4O6 +8 NH3 +6Cl-
Analysis is performed in triplicate. Weigh out
At five minute intervals over the next fifteen minute period, record the color intensity of the solution of each test tube.
We know that that the end point of the titration is reached when, after drop after careful drop of NaOH, the solution in the flask retains its pale pink color while swirling for about 30
2. Write a statement to explain the molecular composition of the unknown solution based on the results obtained during testing with the Biuret solution and each sample solution.
Reaction 3- 1. Obtained a clean and dry test tube and placed a small amount ( about the size of a jelly bean) of ammonium carbonate into the test tube.
Experiment 55 consists of devising a separation and purification scheme for a three component mixture. The overall objective is to isolate in pure form two of the three compounds. This was done using extraction, solubility, crystallization and vacuum filtration. The experiment was carried out two times, both of which were successful.
3. Experiment: Use the Gizmo to find the carrying capacity with Ample, Moderate, and Little land. List the carrying capacities below.
A chemical reaction is when substances (reactants) change into other substances (products). The five general types of chemical reactions are synthesis (also known as direct combination), decomposition, single replacement (also known as single displacement), double replacement (also known as double displacement), and combustion. In this lab, the five general types of chemical reactions were conducted and observations were taken before, during, and after the reaction. Then the reactants and observations were used to determine the products to form a balanced chemical equation. The purpose of this lab was to learn and answer the question: How can observations be used to determine the identity of substances produced in a chemical reaction?
Objectives: The lab experiment will consist of oxidation-reduction and double displacement reactions as well as titration techniques. All these components will be used in order to determine the percent composition of pennies. In conducting redox and double displacement we are able to analyze a penny and figure out the chemical composition of the product. The experiment entails careful observations and recording of evidence for a chemical reaction. In this experiment
a. Change the 24th bead to a different color. What does the sentence say now (re-read the entire sentence)? Does the sentence still make sense?
The results showed the molarity of the NaOH solution. This experiment was completed twice and a new average molarity
deionized water to make a 250 mL solution, the molarity of that solution would be 0.00935 M.
The proof (twice the % alcohol) starts at its maximum and goes down (as the alcohol evaporates). If we start with a high concentration of alcohol, we will get the azeotrope (95% alcohol, 5% water) for a while, then the concentration will decrease.
The luminous yellow flame is smoky because no air is entering the burner and hydrocarbon is converted into carbon dioxide
The molarity of each trial was found using the formula below; following the formula is a sample calculation:
4g of Na CO x 1 mol of Na CO 4g of CaCl x 1mol of CaCl