Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
10th Edition
ISBN: 9780073398204
Author: Richard G Budynas, Keith J Nisbett
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 5, Problem 47P
To determine
The factor of safety for yielding from maximum-shear-stress theory.
The factor of safety for yielding from distortion-energy theory.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
The plate of the figure is subjected to a bending moment with irregular cycles, which are
repeated. In the graphic one of this cycles is represented in terms of stress which appears in
each section whose height is h. The piece is made of ductile steel. Determine the number
of repetitions of the sequence which the piece can resist before the failure takes place due
to fatigue considering a reliability of 95 %.
Data: Sult = 1.000 MPa
Syp 3D800 Mра
thickness e = 4 mm
H = 10 cm
h = 5 cm
r=1 cm
ka = 0,72
kp = 0,95
S(MPa)
M
400
h
300
200
100
W
-100
-200
A shaft made of steel receives 7.5 kW power at 1500 r.p.m. A pulley mounted on the shaft as shown
in Fig. has ratio of belt tensions 4. The gear forces are as follows :
F, = 1590 N; F, = 580 N
Pulley
Gear
F1
A
D
F,
-100 :
200-
100→
All dimensions in mm.
Design the shaft diameter by maximum shear stress theory. The shaft material has the following
properties :
Ultimate tensile strength = 720 MPa; Yield strength = 380 MPa; Factor of safety = 1.5.
Figure 2 shows a solid shaft consisting of two prismatic circular parts in equilibrium under the
torques applied to the pulleys fastened to it. Give that the diameter for part AB and BC are 200
mm and 120 mm, respectively.
(a) Determine the torque, TR on the shaft.
(b) State the segment at which the maximum shearing stress occurs. Verify your answer by
shear stress analysis.
d- 200 mm
d- 120 mm
TA= 36 kN.m
Te=14 kN.m
Ta
C
Figure 2: Solid shaft with pulleys
Chapter 5 Solutions
Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - Prob. 6PCh. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...
Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - A ductile material has the properties Syt = 60...Ch. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - 5-14 to 5-18 An AISI 4142 steel QT at 800F...Ch. 5 - 5-14 to 5-18 An AISI 4142 steel QT at 800F...Ch. 5 - 5-14 to 5-18 An AISI 4142 steel QT at 800F...Ch. 5 - A brittle material has the properties Sut = 30...Ch. 5 - Repeat Prob. 519 by first plotting the failure...Ch. 5 - For an ASTM 30 cast iron, (a) find the factors of...Ch. 5 - For an ASTM 30 cast iron, (a) find the factors of...Ch. 5 - Prob. 23PCh. 5 - For an ASTM 30 cast iron, (a) find the factors of...Ch. 5 - 5-21 to 5-25 For an ASTM 30 cast iron, (a) find...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-31 to 5-35 Repeat Probs. 526 to 530 using the...Ch. 5 - 5-31 to 5-35 Repeat Probs. 526 to 530 using the...Ch. 5 - Repeat Probs. 526 to 530 using the modified-Mohr...Ch. 5 - Repeat Probs. 526 to 530 using the modified-Mohr...Ch. 5 - Repeat Probs. 526 to 530 using the modified-Mohr...Ch. 5 - This problem illustrates that the factor of safety...Ch. 5 - For the beam in Prob. 344, p. 147, determine the...Ch. 5 - A 1020 CD steel shaft is to transmit 20 hp while...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - Prob. 42PCh. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - Prob. 45PCh. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - Prob. 47PCh. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - Build upon the results of Probs. 384 and 387 to...Ch. 5 - Using F = 416 lbf, design the lever arm CD of Fig....Ch. 5 - A spherical pressure vessel is formed of 16-gauge...Ch. 5 - This problem illustrates that the strength of a...Ch. 5 - Prob. 60PCh. 5 - A cold-drawn AISI 1015 steel tube is 300 mm OD by...Ch. 5 - Prob. 62PCh. 5 - The figure shows a shaft mounted in bearings at A...Ch. 5 - By modern standards, the shaft design of Prob. 563...Ch. 5 - Build upon the results of Prob. 340, p. 146, to...Ch. 5 - For the clevis pin of Prob. 340, p. 146, redesign...Ch. 5 - A split-ring clamp-type shaft collar is shown in...Ch. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Two steel tubes have the specifications: Inner...Ch. 5 - Repeal Prob. 5-71 for maximum shrink-fit...Ch. 5 - Prob. 73PCh. 5 - Two steel lubes are shrink-filled together where...Ch. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77PCh. 5 - Prob. 78PCh. 5 - Prob. 79PCh. 5 - Prob. 80PCh. 5 - Prob. 81PCh. 5 - For Eqs. (5-36) show that the principal stresses...Ch. 5 - Prob. 83PCh. 5 - A plate 100 mm wide, 200 mm long, and 12 mm thick...Ch. 5 - A cylinder subjected to internal pressure pi has...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- The figure shows a shaft mounted in bearings at A and D and having pulleys at B and C. The forces shown acting on the pulley surfaces represent the belt tensions. The shaft is to be made of AISI 1035 CD steel. Using distortion-energy theory with a design factor of 2, determine the minimum shaft diameter to avoid yielding.arrow_forwardA motor drives a shaft at 300 rpm and a power output of 100 kW. The shaft is made of A-36 steel and has diameter 128 mm. There are two gears at B and C and power is transmitted to them equally. The bearing at D can be taken to be frictionless. Calculate the maximum shear stress in the shaft, and the angle of twist of D relative to A. The lengths are 2 m, L2 = 3 m, and L3 = 3.5 m. L₁ = A B 030/ 2021 Cathy Zupke X ↳₂ The maximum shear stress is Tmax= 60.9 X MPa The angle of twist (in degrees) between A and D is A/D 58.2 O Carrow_forwardQ-3 A 25-mm-diameter solid round bar has a groove 2.5-mm deep with a 2.5-mm radius machined into it. The bar is made of AISI 1050 CD steel and is subjected to a purely reversing torque of 250 N-m. For the S-N curve of this material, let f= 0.9.arrow_forward
- Let's consider a solid circular shaft subjected to the torque loads as shown Determine the minimum required diameter "D" if the shaft is made of a material having a yielding shear stress Ty = 100 MPa, for a factor of safety FS = 2. The polar moment of inertia of a solid circular cross-section is given by Jr.R¹/2. 300 mm B 600 mm 100 N.m 500 N.m 600 mm 400 N.marrow_forwardThe shaft is made of A-36 steel. It has a diameter of 38 mm and is supported by bearings at A and D, which allow free rotation. The shear modulus of elasticity for A-36 steel is 75 GPa. (Figure 1) Part A Determine the angle of twist of gear C with respect to B. Express your answer using three significant figures. vec Figure 1 of 1> rad Submit Request Answer 90 N-m 0.6 m Provide Feedback Ne 90 N-m 0.75 m 0.9 marrow_forwardThe figure (attached) shows a belt pulley mechanism which is loaded statically. The shaft is made of AISI 1030 steel with the yield strength of 480 MPa. Using distortion energy theory (DET), determine the diameter of the shaft with a factor of safety of 2.arrow_forward
- Two rods are connected by means of a pin joint. The axial force Pacting on the rod is 25 kN. The rods are made of plain carbon steel 45C8 (Syt = 380 N/mm²) and the factor of safety is 2.5. Take the allowable shear stress based on distortion energy theory. What is the diameter of the pin? Pin Rodarrow_forwardThe shear modulus of the solid steel shaft is G = 11 x 10° ksi. Motor A is directly coupled to the shaft and delivers 3 hp while rotating at 1800 rpm (revolutions per minute). Gears B, C, and D remove the powers indicated in the figure. Given the following two criteria, determine the required diameter of the shaft to the nearest 1/s in. (1) The maximum shear stress must not exceed Tallow = 9 ksi. (2) In order to prevent binding or interference in the attached machin- ery, the angle of twist of gear B with respect to gear D must not exceed 1°. 1.25 ft 1.0 ft 3 hp 1.5 ft 1 hp 0.5 hp 1.5 hparrow_forwarda) by using maximum shear stress theory of failure b) by using distortion energy theory of failure. Problem 4.2 The stepped shaft shown in Figure below is subjected to a tensile load of 32 kN and to a torque of 150 Nm. If the shaft is made of steel having S-830 MPa, S,-620 MPa and E=207 Gpa, determine factor of safety by using distortion energy theory of failure. T r=2.8 T 24 16 Dimensions are in mmarrow_forward
- An aluminum alloy is to be used for a solid drive shaft such that it transmits 30 hp at 1200 rev>min. Using a factor of safety of 2.5 with respect to yielding, determine the smallest-diameter shaft that can be selected based on the maximum shear stress theory. sY = 10 ksi.arrow_forward5-63 The figure shows a shaft mounted in bearings at A and D and having pulleys at B and C. The forces shown acting on the pulley surfaces represent the belt tensions. The shaft is to be made of AISI 1035 CD steel. Using a conservative failure theory with a design factor of 2, determine the minimum shaft diameter to avoid yielding. f-in R 300 Ibf 50 lbf 59 Ibf 392 lbf D Problem 5-63 C 6 in 8-in D. 8 in B 8 inarrow_forwardA winch raises a 60# bucket of paint, as shown. The main shaft of the winch is simply supported by bearings at A and C. The winch uses a 6"diameter pulley (B) and torque is applied at the end of the shaft to pull the cart. Determine the minimum shaft diameter based on the Distortion Energy (Von Mises) criterion using on a yield strength of 50ksi and a design factor of 2.0. 12" winch 18" C A Paint Ropearrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning