Principles of Foundation Engineering (MindTap Course List)
Principles of Foundation Engineering (MindTap Course List)
9th Edition
ISBN: 9781337705028
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 2, Problem 2.8P
To determine

Find the amount of water flowing into the ditch per day.

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2.8 A 500 m long levee made of compacted clay impounds water in a reservoir as shown in Figure P2.8. There is a 1 m thick (measured in the direction perpendicular to the seam) sand seam continuing along the entire length of the levee, at 10° inclination to the horizontal, which connects the reser- voir and the ditch. The hydraulic conductivity of the sand is 2.6 × 10-³ cm/s. Determine the volume of water that flows into the ditch every day.
Given the following: H1 = 1.5 m H2 = 3.0 m H3 = 2.0 m K1 = 0.001 cm/sec K2 = 0.032 cm/sec K3 = 0.000041 cm/sec 1. Find the effective average permeability of the deposit in the horizontal direction. (in cm/s) 2. Find the effective average permeability of the deposit in the vertical direction. (in cm/s) 3. What is the ratio of the equivalent hydraulic conductivity?
1. (30 pts) The soil profile shown below consists of 10 meters of sandy silt overlying gravel. The pore water pressure at the top surface of the silty sand is zero and can be assumed to remain zero. a) Calculate the level to which water would rise in a piezometer tube inserted into the top of the gravel if the silty sand is just stable? Use submerged unit weights and seepage forces to arrive at your answer (do not calculate total stresses and pore water pressures). Express your answer as an elevation, e.g. "Elev. 130". (Note: Elevations are in meters) (10 pts) b) Using the piezometric elevation calculated in part (a), calculate the pore water pressure at the bottom of the silty sand if the silty sand is just stable (10 pts). c) Calculate the total stress at the base of the silty sand and show that it is equal to the pore water pressure calculated in part (b) (10 pts) Elev. 120 m. Elev. 110 m. Sandy Silt (saturated) Void ratio, e = 0.68 G = 2.65 Gravel
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