When the ions at their equilibrium interionic separation, the force of attraction between a divalent (valency of 2) cation and a monovalent (valency of 1) anion is 7.32 × 10−9 N. If the ionic radius of the cation is 0.05 nm, what is the anion radius (nm)? Round your result to 2 decimal place.
When the ions at their equilibrium interionic separation, the force of attraction between a divalent (valency of 2) cation and a monovalent (valency of 1) anion is 7.32 × 10−9 N. If the ionic radius of the cation is 0.05 nm, what is the anion radius (nm)? Round your result to 2 decimal place.
University Physics Volume 3
17th Edition
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:William Moebs, Jeff Sanny
Chapter9: Condensed Matter Physics
Section: Chapter Questions
Problem 58P: The measured density of a CsCl crystal is 3.988 g/cm3. What is the equilibrium separate distance of...
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When the ions at their equilibrium interionic separation, the force of attraction between a divalent (valency of 2) cation and a monovalent (valency of 1) anion is 7.32 × 10−9 N. If the ionic radius of the cation is 0.05 nm, what is the anion radius (nm)?
Round your result to 2 decimal place.
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