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- A:08 الرسائل المحفو. . . 1 03: Rhenium has a Hexagonal Close-Packed crystal structure with an atomic radius of 0.137 nm and a ratio c/a of 1.615, compute: a) The volume of the unit cell. b) The theoretical density c) Atomic packing factor Note: Avogadro's' number = 6.023×10²³ Atomic weight = 186.21 g/mol إضافة وصف.. . IIIGiven: Molybdenum has a BCC crystal structure, an atomic radius of 0.1363 nm, and an atomic weight of 95.64 g/mol. Required: Calculate the theoretical density of molybdenum. Compare your calculated density to the experimentally measured density of 10.22 g/cm3.The edge length of a unit cell of a crystal is 4.3 Angstrom and an atomic mass of 90 g/mol. If the density of the crystal is 9.02 g/cm3, find the number of atoms in a unit cell.
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- 4) Molybdenum has a BCC crystal structures, the density of molybdenum is 10.22 g/cm³ and its atomic mass is 95.94 g/mol. What are the atomic concentration, the lattice parameter a and the atomic radius of molybdenum. What is the atomic concentration in the primitive cell? 5) Tungsten (W) has the BCC crystal structure. The radius of the W atom is 0.1371 nm. The atomic mass of W is 183.8 amu (g/mol). Calculate the number of W atoms per unit volume and the density of W (NA = 6.02 x 10²3).The density of potassium, which has the FCC structure and one atom per lattice point, is 0.855 g/cm3. The atomic weight of potassium is 39.09 g/mole and Avogadro's number, NA= 6.02*1023 atom/mol. The lattice parameter for this structure is equal to: O a. a,= 6.7223*10 8 cm O b. ao= 5.6355*108 cm O c. a,= 6.3355*108 cm O d. ao= 5.3355*10 8 cmSolve for the Fermi temperature OF(K), effective mass ratio m* /me and electron concentration no for the Lithium element. Element Li Fermi energy EF (eV) 4.7 Fermi velocity VF (108 cm/s) 1.3 Fermi temperature OF (K) effective mass ratio m/me ~1 electron concentration = N nf = (10¹⁹ cm-³) V