Living By Chemistry: First Edition Textbook
Living By Chemistry: First Edition Textbook
1st Edition
ISBN: 9781559539418
Author: Angelica Stacy
Publisher: MAC HIGHER
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Chapter U6.4, Problem 4E

(a)

Interpretation Introduction

Interpretation: The equilibrium constant for the following reaction needs to be calculated and the reaction favors products or not is to be determined.

  2CO(g)+O2(g)2CO2(g)

Concept Introduction : The equilibrium constant K is a measure of whether starting substances or products are favored in an equilibrium mixture. A large value of K indicates a large amount of product in the equilibrium mixture. A small value of K indicates very little product in the equilibrium mixture.

(a)

Expert Solution
Check Mark

Answer to Problem 4E

Value of K is 1.024×105 . So, the equilibrium favors products.

Explanation of Solution

The given reaction is as follows:

  2CO(g)+O2(g)2CO2(g)

  K=[CO2]2[O2][CO]2=[3.2×102]2[1.6×103][2.5×103]2=10.24×1041.6×103×6.25×106=10.24×10410×109=1.024×105

As value of K is large, the equilibrium favors products.

(b)

Interpretation Introduction

Interpretation: The equilibrium constant for the following reaction needs to be calculated and the reaction favors products or not is to be determined.

  N2(g)+3H2(g)2NH3(g)

Concept Introduction : The equilibrium constant K is a measure of whether starting substances or products are favored in an equilibrium mixture. A large value of K indicates a large amount of product in the equilibrium mixture. A small value of K indicates very little product in the equilibrium mixture.

(b)

Expert Solution
Check Mark

Answer to Problem 4E

Value of K is 1.521×101 and the equilibrium favors reactants.

Explanation of Solution

Given concentrations are as follows:

  [H2]=1.2×101[NH3]=3.4×103[N2]=4.4×102

Now calculate K for N2(g)+3H2(g)2NH3(g) .

  K=[NH3]2[N2][H2]3=(3.4×103)24.4×102×(1.2×101)3=11.56×1064.4×102×1.728×103=11.56×1067.60×105=1.521×101

As the K value is smaller, the equilibrium favors reactants.

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