Chapter SH, Problem 13.6.8EP

To determine

To find:the probability $P(\text{ neither blue nor yellow})$

Answer to Problem 13.6.8EP

The required probability is $\frac{3}{5}\text{ or }60\%$

Explanation of Solution

Given:

Number of blue marbles is 4

Number of red marbles is 6

Number of green marbles is 3

Number of yellow marbles is 2

Select one marble at random.

Calculation:

Total number of marbles is $4+6+3+2=15$

Number of blue or yellow marbles is $4+2=6$ .

  $\begin{array}{l}P(\text{blue or yellow})=\frac{\text{ number of blue or yellow marbles }}{\text{ total number of marbles }}\\ =\frac{6}{15}\\ =\frac{2}{5}\\ P(\text{neither blue nor yellow})=1-\frac{2}{5}\\ =\frac{3}{5}\\ =60\%\end{array}$

Hence, the required probability is $\frac{3}{5}\text{ or }60\%$

Conclusion:

Therefore, the required probability is $\frac{3}{5}\text{ or }60\%$