PRECALCULUS:GRAPHICAL,...-NASTA ED.
PRECALCULUS:GRAPHICAL,...-NASTA ED.
10th Edition
ISBN: 9780134672090
Author: Demana
Publisher: PEARSON
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Chapter P, Problem 32RE
Solution

The equation of the line in slope-intercept form with given equation.

  y=52x+2

Given information:

The line passes through the point 2,3 and is perpendicular to the line 2x+5y=3 .

Formula used:

  1. The equation of the lie in slope-intercept form that passes through a point x1,y1 with a slope m is given as: y=mx+c, where c can be find putting the point in the equation.
  2. The multiplication of slope of two perpendicular lines is equals to 1 .

Calculation:

To find the slope intercept form use the point-slope form of equation of line that passes through point 2,3 , and is perpendicular to the line 2x+5y=3 , use the fact that the multiplication of slope of two perpendicular lines is equals to 1 .

First, find the slope of the line 2x+5y=3 by writing it’s equation in the form, y=mx+c , here m is slope, as

  2x+5y=35y=32xy=1532xy=3525xy=25x+35

Comparing above equation with y=mx+c gives the slope of this equation,

  m=25

Now find the slope of the line perpendicular to this line, since the the multiplication of slope of two perpendicular lines is equals to 1 , so the slope of the line, say m2 can be find as

  m×m2=125×m2=1m2=125m2=52

Thus, the equation of the line can be written by using

  y=m2x+cy=52x+c

Now, since the line passes through the point 2,3 putting it in place of x,y find c as

  3=522+cc+5=3c=3+5c=2c=195

Thus, the slope intercept form of the line is

  y=52x+2

Chapter P Solutions

PRECALCULUS:GRAPHICAL,...-NASTA ED.

Ch. P.1 - Prob. 1ECh. P.1 - Prob. 2ECh. P.1 - Prob. 3ECh. P.1 - Prob. 4ECh. P.1 - Prob. 5ECh. P.1 - Prob. 6ECh. P.1 - Prob. 7ECh. P.1 - Prob. 8ECh. P.1 - Prob. 9ECh. P.1 - Prob. 10ECh. P.1 - Prob. 11ECh. P.1 - Prob. 12ECh. P.1 - Prob. 13ECh. P.1 - Prob. 14ECh. P.1 - Prob. 15ECh. P.1 - Prob. 16ECh. P.1 - Prob. 17ECh. P.1 - Prob. 18ECh. P.1 - Prob. 19ECh. P.1 - Prob. 20ECh. P.1 - Prob. 21ECh. P.1 - Prob. 22ECh. P.1 - Prob. 23ECh. P.1 - Prob. 24ECh. P.1 - Prob. 25ECh. P.1 - Prob. 26ECh. P.1 - Prob. 27ECh. P.1 - Prob. 28ECh. P.1 - Prob. 29ECh. P.1 - Prob. 30ECh. P.1 - Prob. 31ECh. P.1 - Prob. 32ECh. P.1 - Prob. 33ECh. P.1 - Prob. 34ECh. P.1 - Prob. 35ECh. P.1 - Prob. 36ECh. P.1 - Prob. 37ECh. P.1 - Prob. 38ECh. P.1 - Prob. 39ECh. P.1 - Prob. 40ECh. P.1 - Prob. 41ECh. P.1 - Prob. 42ECh. P.1 - Prob. 43ECh. P.1 - Prob. 44ECh. P.1 - Prob. 45ECh. P.1 - Prob. 46ECh. P.1 - Prob. 47ECh. P.1 - In Exercises 4752, simplify the expression. Assume...Ch. 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